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2008 Feb 08
0
[PATCH] Make outputDeviceForGeometry behave smarter when dealing with overlapping outputs. Currently, the current output is returned if some part of the rectangle is on it; otherwise the output device the rectangle center is on is returned. This works
...highestScore) + seen++; + + if (seen > 1) { - output = outputDeviceForPoint (s, x + width / 2, y + height / 2); + /* it's not unique, so find the head which is more overlapped by + the window, which in turns means finding the smallest of the + given heads */ + unsigned int currentSize, smallestHead = UINT_MAX; + + for (i = 0, highest = 0; i < s->nOutputDev; i++) + if (overlapAreas[i] == highestScore) + { + BOX *box = &s->outputDev[i].region.extents; + + currentSize = (box->x2 - box->x1) * (box->y2 - box->y1); + if (currentSize < smallestHea...