search for: cumming

Hi all, as I am trying to move slowly from just "working" to "good" code, I'd like to ask if there's a smarter way than using a for-loop in tasks like the example below. I need to obtain the extrema of the cumulated sum of a detrended time series. The following code is currently used, please have a look at the comments for my questions and remarks: system.time({ X

Hello, Looking over the swap_tail macro in pnorm.c, the comment inside the code indicates it is to swap the values of '*cum' and '*ccum'. According to the code below that is taken from the source file, the swap functionality is dependent on what values are provided for 'x' and 'lower'. #define swap_tail \ if (x > 0.) {/* swap ccum <--> cum */

I want to display cumulative summary functions with lattice. First I tried to get cumulated data: library(lattice) data(barley) d.cum <- with( barley, by( yield, INDICES=list(site=site,year=year), FUN=cumsum ) ) I got a list of vectors. I tried to get a dataframe which I could use in xyplot. But neither of the following functions led to the goal: d.cum.df1 <-

sorry for the late reply. i dunno if anyone ever wrote you back. although perhaps not written for clarity, i think what appears in the code is correct. the routine only guarantees that one of cum or ccum has a valid return value depending on i_tail (the other might as well be garbage, but that isn't what's returned). j On Wed, 9 Jul 2003 Henrik.Seidel@schering.de wrote: >

Dear colleagues, I have a data set that looks roughly like this; mydat<-data.frame(state=c(rep("Alabama", 5), rep("Delaware", 5), rep("California", 5)), news=runif(15, min=0, max=8), cum.news=rep(0, 15)) For each state, I'd like to cumulatively sum the value of "news" and make that put that value in cum.news. I'm trying as follows but I get

hello, please can anyone help me out. Am a new user of R program. Am having problem with this code below, not getting the expected results. 1. Each m, the cumulative sum should be 1.000 but the 2nd and 3rd m returned 2.000 and 3.000 instead of 1.000. 2. to get the LCL(m) and UCL(m) for each m base on these instructions if out.cum > 0.025 then LCL(m)= y-1 if out.cum >0.975

Dear R-users, I have a dataset with categories and numbers. I would like to compute and add cumulative numbers to the dataset. I do not understand the structure of by(...) or tapply(...) output enough to handle it. Here a small example -------------- d<-expand.grid(a=1:5,b=1:3,c=1:2) d$n = 10 * d$a + d$b +0.1* d$c Sn<-by(d$n,list(d$a,d$c),cumsum) str(Sn) --------- List of 10 $ : num

I have a data set like the following: subject visit x1 1 1 0.5 1 2 1.2 1 3 0.7 2 1 0.4 2 2 0.6 2 3 1.0 ..... where x1 is the interval between the two visits. Now I want to calculate the cumulative intervals since the beinging, for example subject visit x1 cum 1 1 0.5 0.5 1 2 1.2 0.5+1.2 1 3 0.7 0.5+1.2+0.7 2 1 0.4 0.4 2 2 0.6 0.4+0.6 2 3 1.0 0.4+0.6+1.0 ..... is there an easy to generate the

...lbox Trash { special_use = \Trash } prefix = } passdb { driver = pam } ssl = required ssl_cert = </etc/pki/dovecot/certs/dovecot.pem ssl_cipher_list = PROFILE=SYSTEM ssl_dh = # hidden, use -P to show it ssl_key = # hidden, use -P to show it userdb { driver = passwd } -- Kevin J. Cummings cummings at kjchome.homeip.net cummings at kjc386.framingham.ma.us kjchome at icloud.com Registered Linux User #1232 (http://www.linuxcounter.net/) -------------- next part -------------- An HTML attachment was scrubbed... URL: <https://dovecot.org/pipermail/dovecot/attachments/20180404/deaafc...

Hi, The function cummax() seems to have a bug. > x <- c(NA, 0) > storage.mode(x) <- "integer" > cummax(x) [1] NA 0 The correct result of this case should be NA NA. The mistake in [ https://github.com/wch/r-source/blob/trunk/src/main/cum.c#L130-L136] may be the reason. Best Regards, Dongcan -- Dongcan Jiang Team of Search Engine & Web Mining School of Electronic

Hi Could anyone please suggest a good Payroll cum HR management open source rails application? Thanks Tom -- Posted via http://www.ruby-forum.com/. -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFF+G/Ez6ZCGd0@public.gmane.org To unsubscribe from this

hello, please can anyone help me out. Am a new user of R program. Am having problem with this code below, not getting the expected results. Each m, the cumulative sum should be 1.000 but the 2nd and 3rd m returned 2.000 and 3.000 instead of 1.000. thanks Aruike pp=function(x,n,M){z=1.0;a=2.3071430;b=7.266064;H=3 out.h=c() out.y=c() out.m=c() out.prob=c()

Hello R-Community, we are running aprogram to fit Non-linear differential equations to Aphid population Data and to estimate the birth and death parameters, here is the code: dat<-data.frame(Time=c(0:60),Cur=c(5,6.2,59,39,38,44,20.4,19.4,34.2,35.4,38.2,48.2,55.4,113.2, 97,112,115,126,136.6,140.6,147.2,151.6,157.8,170,202,210.4,221.2,224.4,248.2,266,

Dear R-users, I'm studing a DB, structured like this (just a little part of my dataset): _____________________________________________________________________________________________________________ Site Latitude Longitude Year Tot-Prod Total_Density dmp Dendoudi-1 15.441964 -13.540179 2005 3271.16 1007 16993.25 Dendoudi-2 15.397321 -13.611607

hello, please can anyone help me out. Am a new user of R program. Am having problem with this code below, not getting the expected results. 1. Each m, the cumulative sum should be 1.000 but the 2nd and 3rd m returned 2.000 and 3.000 instead of 1.000. 2. to get the LCL(m) and UCL(m) for each m base on these instructions if out.cum > 0.025 then LCL(m)= y-1 if out.cum

Hi, My objective is to calculate "Relative (Cumulative) Frequency of Event Occurrence" - something as follows: Sample.Number 1st.Fly 2nd.Fly Did.E.occur? Relative.Cum.Frequency.of.E 1 G B No 0.000 2 B B Yes 0.500 3 B G No 0.333 4 G B No 0.250 5 G G Yes 0.400 6 G B No 0.333 7 B B Yes 0.429 8 G G Yes 0.500 9 G B No 0.444 10 B B Yes 0.500 Please refer to the code below:

Timo - I upgraded to 2.1.10 on our director servers two nights ago and apart from errors associated with the directors processes restarting everything looked great for ~24 hours until I failed our the real servers last night to update the nfs mount options for the spools. I followed the suggested procedure for each backend server, just run on one of the directors, which seemed to work as

as used on Illumos? I''ve seen a few tutorials written by people who obviously are very action oriented; afterwards you find you have worn your keyboard down a bit and not learned a lot at all, at least not in the sense of understanding what zfs is and what it does and why things are the way they are. I''m looking for something that would make me afterwards understand what,

Dear all, I would like to create a vertically stacked area chart in R. The data are presented in the attached text file. I would like to see the trend in values for the different groups with sediment depth (that's why I would like to create a vertically stacked chart; normally sed_depth should be = x, but I want it plotted on the y-axis). In the packages available to create stacked area

Hi, Maybe I have not been looking in the right spot, but, I have not been able to fine a command to automatically calculate the running cumulative sum of a vector. Is there such a command? Example of current code: > eig$values [1] 678.365651 6.769697 2.853783 > prop<-eig$values/sum(eig$values) > prop [1] 0.986012163 0.009839832 0.004148005 >