Displaying 1 result from an estimated 1 matches for "cudata".
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udata
2005 Apr 27
1
making table() work
I am trying to do some verification across a large dataset, cuData, that
has 23 columns.
Column 23 (similarity) is the outcome 0 or 1 and the other columns are
the features.
I do this:
verificationglm.model <- glm(formula = similarity ~ ., family=binomial,
data=cuData[1:1000,])
and produce the model:
> summary(verificationglm.model)
Call:
glm(for...