Displaying 1 result from an estimated 1 matches for "coviarate2".
Did you mean:
covariate2
2010 Jun 04
2
using string as variable name in model
...zCANTAB_sqrt_SWM_Total
13 13 zSS_WJ_PC
14 14 zSS_WJ_CALC
15 15 zSS_WJ_LW
16 16 zSS_WJ_AP
17 17 zSS_WJ_MF
What I'm trying to do is
varnames[1,2] -> outcome
lm(outcome ~ income + covariate1 + coviarate2, data=my.data) -> model
I get the following error message:
"Error in model.frame.default(formula = outcome ~ Hollings_Enroll + Child_sex + :
variable lengths differ (found for 'Hollings_Enroll')"
But when I run the model:
lm(zCANTAB_log_IED_totaltrials ~ income + covariat...