Displaying 7 results from an estimated 7 matches for "count8".
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2017 Nov 09
3
Calculating frequencies of multiple values in 200 colomns
...-
> Values
A B C ... 200
1 7 10 7
2 7 8 7
3 10 8 7
4 8 7 10
.
.
.
1000
For column A : I calculate the frequency for the 3 values as follows :
count7 <- length(which(Values$A == 7))
count8 <- length(which(Values$A == 8))
count10 <- length(which(Values$A == 10))
count7 = 2, count8 = 1 , count10= 1.
Then, I create a vector and type the frequencies manually :
Freq<- c( count7=2 ,count8= 1,count10=1)
Then I apply the function maf () :-
maf(Freq)
This gives me the...
2017 Nov 09
2
Calculating frequencies of multiple values in 200 colomns
...t;
>> 4 8 7 10
>>
>> .
>>
>> .
>>
>> .
>>
>> 1000
>>
>>
>> For column A : I calculate the frequency for the 3 values as follows :
>>
>> count7 <- length(which(Values$A == 7))
>>
>> count8 <- length(which(Values$A == 8))
>>
>> count10 <- length(which(Values$A == 10))
>>
>>
>> count7 = 2, count8 = 1 , count10= 1.
>>
>>
>> Then, I create a vector and type the frequencies manually :
>>
>>
>> Freq<- c( count7=2...
2017 Nov 10
0
Calculating frequencies of multiple values in 200 colomns
...is :-
> Values
A B C ... 200
1 7 10 7
2 7 8 7
3 10 8 7
4 8 7 10
.
.
.
For column A : I calculate the frequency for the 3 values as follows :
count7 <- length(which(Values$A == 7))
count8 <- length(which(Values$A == 8))
count10 <- length(which(Values$A == 10))
count7 = 2, count8 = 1 , count10= 1.
Then, I create a vector and type the frequencies manually :
Freq<- c( count7=2 ,count8= 1,count10=1)
Then I apply the function maf () :-
maf(Freq)
This gives me the...
2007 Oct 19
0
calculating power of log rank test
...to calculate the power of the logrank test for different values of rho .I was just wandering whether the following programme would do it. any suggestions are welcome
s=50
number=1
count1=0;count2=0;count3=0;count4=0;count5=0;count6=0;count7=0;count7=0;
count8=0;count9=0
while(s!=0){
n=20
n1=n/2
n2=n/4
a11=1 ;a12=1.4 ;a21=16 ;a22=a12 * a21
t1<-array(1,c(n1))
t2<-array(2,c(n1))
treatgrp=matrix(c(t1,t2))...
2008 Feb 14
0
help in simplyfiying programme
my program given below can some one make it presentable. I trying to simulate survival data and calculate the power. I think i could have done better.
s=10
number=0
count1=0;count2=0;count3=0;count4=0;count5=0;count6=0;count7=0;count8=0;
count9=0;
count11=0;count22=0;count33=0;count44=0;count55=0;count66=0;count77=0;
count88=0;count99=0;
while(s!=0){
n=100
n1=n/2
n2=n/4
t1<-array(1,c(n1))
t2<-array(2,c(n1))
treatgrp=matrix(c(t1,t2))...
2017 Nov 10
2
Calculating frequencies of multiple values in 200 colomns
...7 8 7
>
> 3 10 8 7
>
> 4 8 7 10
>
> .
>
> .
>
> .
>
>
>
>
> For column A : I calculate the frequency for the 3 values as follows :
>
> count7 <- length(which(Values$A == 7))
>
> count8 <- length(which(Values$A == 8))
>
> count10 <- length(which(Values$A == 10))
>
>
> count7 = 2, count8 = 1 , count10= 1.
>
>
> Then, I create a vector and type the frequencies manually :
>
>
> Freq<- c( count7=2 ,count8= 1,count10=1)
>
>
>...
2017 Nov 10
0
Calculating frequencies of multiple values in 200 colomns
...>> 4 8 7 10
>>
>> .
>>
>> .
>>
>> .
>>
>>
>>
>>
>> For column A : I calculate the frequency for the 3 values as follows :
>>
>> count7 <- length(which(Values$A == 7))
>>
>> count8 <- length(which(Values$A == 8))
>>
>> count10 <- length(which(Values$A == 10))
>>
>>
>> count7 = 2, count8 = 1 , count10= 1.
>>
>>
>> Then, I create a vector and type the frequencies manually :
>>
>>
>> Freq<- c( cou...