search for: corneli

I am interested in testing two similar nls models to determine if the lines are statistically different when fitted with two different data sets; one corn, another soybean. I know I can do this in linear models by testing for interactions. See Introductory Statistics with R by Dallgaard p212-218 for an example. I have two different data sets I am comparing to lai. ci.re should have very

Hello, I have a simple question but I don't know which method is best to use for my problem. I have the following strings: str1 <- "My_name_is_peter" str2 <- "what_is_your_surname_peter" I would like to apply predefined abbreviations for peter=p and name=n to both strings so that the new strings look like the followings: str1: "My_n_is_p" str2:

Dear group, Here is my df, trades1 : trades1 <- structure(list(Instrument.Long.Name = c("CORN", "CORN", "CORN", "CORN", "CORN", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "STANDARD LEAD USD", "STANDARD LEAD USD", "SPCL

Dear group, I need to modify some characters in a data frame. I want to use gsub and the regex functionalities to do this. Here is the data frame (df): DESCRIPTION prix quantity 1 CORN Jul/10 -1.5 0 2 CORN May/10 -1082.0 -3 3 ROBUSTA COFFEE (10) Jul/10 11084.0 8 4 SOYBEANS Jul/10 1983.5

Dear group, Here is my data frame: futures <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10", "LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11

Dear group, I have these 2 following data frame: allcon <- structure(list(DESCRIPTION = structure(1:17, .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB NATURAL GAS May/10", "ROBUSTA COFFEE (10)

Dear group, Here is the kind of data.frame I obtain every day with my function : futures <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10", "LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR

Dear group, Here is my df : trades <- structure(list(Trade.Status = c("DEL", "INS", "INS"), Instrument.Long.Name = c("SUGAR NO.11", "CORN", "CORN"), Delivery.Prompt.Date = c("Jul/10", "Jul/10", "Jul/10"), Buy.Sell..Cleared. = c("Sell", "Buy", "Buy"), Volume = c(1L, 2L, 1L),

Dear group, I have 3 data frames I would like to merge. Here they are: pose16 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11

Dear group, Here is my df: avprix <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN May/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SPCL HIGH GRADE ZINC USD", "STANDARD LEAD USD"), prix = c(-1.5, -1082, 11084, 1983.5, -2464, -118), quantity = c(0, -3, 8, 2, -1, 0), fees = c(-8.64, -30.24, -26.4, -25.92, -37.5,

Dear R-list, Is there any way I can extract part or whole column name from two variables and combine them? Not values, but column names. For example, I have data set with 70 variables. The column names are "Alfalfa", "Corn","Soybean",..."Sunflower". After I combine the two variable (say Alfalfa and Corn), I want to rename it as "AlfCor" or

Dear group, Here is my data frame: > dput(u) structure(list(DESCRIPTION = structure(c(2L, 5L, 6L, 7L, 9L, 11L, 12L, 15L, 14L, 16L, 1L, 10L, 3L, 4L, 13L, 8L, 17L), .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB

Dear group, Here is my df : df3 <- structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10", "WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD",

Hi List l am interested in developing price model. I have found a research paper related to price model of corn in US market where it has taken demand & supply forces into consideration. Following are the equation: Supply equation: St= a0+a1Pt-1+a2Rt-1+a3St-1+a5D1+a6D2+a7D3+U1 -(1) Where D1,D2,D3=Quarterly Dummy Variables(Since quarterly data are considered) Here, Supply

Dear list, here are my two data frames: av <- structure(list(DESCRIPTION = c("COFFEE C Sep/10", "COPPER Sep/10", "CORN Dec/10", "CRUDE OIL miNY Sep/10", "GOLD Aug/10", "HENRY HUB NATURAL GAS Sep/10", "PALLADIUM Sep/10", "SILVER Sep/10", "SOYBEANS Nov/10", "SPCL HIGH GRADE ZINC USD", "SUGAR

Hello, I run CentOS release 6.10 (Final) on a Dell Inspiron M6700. 2.6.32-754.el6.x86_64 boots, and is whaat I am running now none of these, updated ones, won't boot: 2.6.32-754.3.5.el6.x86_64 2.6.32-754.6.3.el6.x86_64 2.6.32-754.9.1.el6.x86_64 2.6.32-754.10.1.el6.x86_64 They all show the same 'symptom',? grub says it is booting that kernel, screen blanks, solid corned in

Dear group, Here is my df : trade <- structure(list(Trade.Status = c("DEL", "INS", "INS"), Instrument.Long.Name = c("SUGAR NO.11", "CORN", "CORN"), Delivery.Prompt.Date = c("Jul/10", "Jul/10", "Jul/10"), Buy.Sell..Cleared. = c("Sell", "Buy", "Buy"), Volume = c(1L, 2L,

Hi everyone, I'm trying to print a table justified to the left, but it doesn't work. Any hints? KennArt <- data.frame(NR=c(171,172,174,175,176,177,181,411,980), TYP=c("K?rnermais", ?"Corn Cob Mix", "Zuckermais", "Mischanbau (Silo)Mais/Sonnenblumen", ?"Mais mit Bejagungsschneise in gutem landwirtschaftlichen und ?kologischen Zustand",

I've been working on the local side of asterisk for several days, and I have the in-house dial plan pretty well corn fingered to my satisfaction. Today I began working on the other side to make asterisk do things like place an outgoing call to PSTN and route an incoming call from PSTN. I'm using a TDM11B with a single fxs and a single fxo. My analog handset is plugged into the port

Dear List, I have got error message when I run the R-code. Can anyone has a suggestion? v.code <- df.bm7[,c(10:31)]; v.code[1:3,] names(v.code) CM = v.code # variable binomial code sim.sp <- function(data,CM,n,N) { C <- matrix(rep(NA,N),ncol=1) for(i in 1:N) { j <- n xx <- which(colSums(CM[j,])==1) V <- names(xx) V <- paste(V,