Displaying 3 results from an estimated 3 matches for "control_".
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2004 Nov 12
0
Design Matrix
Dear all,
I need some help on matrix design and B statistics by using limma package.
I want to compare gene expression in 2 groups of cDNA samples.
The experiment compares 4 treated mice(#1,#2,#3,#4) and 4 control mice
(#5,#6,#7,#8).
The target file is
FileName Cy3 Cy5
mice1.spot Control_#5 Treat_#1
mice2.spot Treat_#1 Control_#5
mice3.spot Control_#6 Treat_#2
mice4.spot Treat_#3 Control_#7
mice5.spot Control_#8 Treat_#4
The first slide (mice1.spot) and the second slide(mice2.spot) are
dye-swap. There is no common reference. There are 3 replicated spots of
eac...
2017 Dec 02
0
How can you find the optimal number of values to randomly sample to optimize random forest classification without trial and error?
...nt3)
To classify these samples as either control or patient, I want make
frequency distributions of presence of each of the 100 variables being
considered. To do this, I randomly sample "s" values from each sample and
generate a frequency vector of length 100. This is how I would do it:
control_s <- list()
patient_s <- list()for (i in 1:length(control))
control_s[[i]] <- sample(control[[i]], s)for (i in 1:length(patient))
patient_s[[i]] <- sample(patient[[i]], s)
Once I do this, I generate the frequency vector of length 100 as follows:
controlfreq <- list()...
2006 Mar 08
23
rubynuby == I''m a''scared to set it all up...
I''ve been mostly lurking here with an occasional nuby question for a few
weeks now. It seems like Ruby and Rails and the many libraries and
tools growing up around it are a remarkable toolset. Unfortunately I''m
finding the whole enchilada a bit daunting.
It seems that if one is to truly tap into the power of this thing and do
a significant amount of developing, one needs