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...My expectation was that unlist(y, recursive=FALSE) would be the following length 3 list: list(a1=1, a2=2, b=list(b1=3:4, b2=5:6)) However str(unlist(y, recursive=FALSE)) ## List of 4 ## $ a1 : int 1 ## $ a2 : int 2 ## $ b.b1: int [1:2] 3 4 ## $ b.b2: int [1:2] 5 6 I'm tempted to say that, contary to the documentation, (partial) unlisting has in fact been applied to a list component of x (x$b): it contributes 2 components to the result, rather than one. I say partial because the numeric vectors in x$b have not been broken up into separate elements in the answer. However, I imagine that this...