search for: conitain

Joris, the point is that 'z' is NOT used as a predictor in the model. Therefore it should not affect predictions. Also, I find it suspicious that the error only occurs when the response variable conitains missings and 'z' is unique (I have tested several other cases to confirm this). -Mark Op vr 16 mrt. 2018 om 13:03 schreef Joris Meys <jorismeys at gmail.com>: > It's not a bug per se. It's the effect of removing all observations linked > to a certain level in your da...

Hi, I am looking for a way to search a file for position of some expression, from within R. My current code: sha1Pos = gregexpr("<sha1>", readChar(filename, file.info(filename)$size))[[1]] Works fine for small files, but text files I will be working with might get up to Gb range, so I was trying to accomplish the same without loading the whole file into R. I realize this is

...16, 2018 at 1:09 PM, Mark van der Loo <mark.vanderloo at gmail.com> wrote: > Joris, the point is that 'z' is NOT used as a predictor in the model. > Therefore it should not affect predictions. Also, I find it suspicious that > the error only occurs when the response variable conitains missings and 'z' > is unique (I have tested several other cases to confirm this). > > -Mark > > Op vr 16 mrt. 2018 om 13:03 schreef Joris Meys <jorismeys at gmail.com>: > >> It's not a bug per se. It's the effect of removing all observations >> l...

Dear R-developers, In the 'lm' documentation, the '-' operator is only specified to be used with -1 (to remove the intercept from the model). However, the documentation also refers to the 'formula' help file, which indicates that it is possible to subtract any term. Indeed, the following works with no problems (the period '.' stands for 'all terms except the