Displaying 2 results from an estimated 2 matches for "confidenc".
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confidence
2010 Dec 20
1
Metafor package
...ni+1)))). Hovewer, i also found the same formula but
without 1/2*.
2. how "vi", the corresponding (estimated) sampling variance is
calculated? (i.e. the formula used to estimate "vi")
3. it is possible to return a forest plot with the backtransformed
value of proportion, confidenc interval and weight and not with the
transformed value after performing rma.uni?
Many thanks
Mario Petretta
Dipartimento di Medicina Clinica Scienze Cardiovascolari e Immunologiche
Facolt? di Medicina e Chirurgia
Universit? di Napoli Federico II
081 - 7462233
2002 Aug 07
2
Constructing titles from list of expressions
...var.names <- var.names[b]
}
var.names <- var.names[1:3]
resp.name <- names(x.lm$model)[1]
ranges <- t(apply(data[,var.names], 2, range))
extremum <- as.list(extremum)
names(extremum) <- var.names
schaetz <- predict(x.lm, as.data.frame(extremum), interval="confidence", level
=conf.level)
result <- list(prognose=schaetz[1], conf.interval=schaetz[-1], conf.level=conf
.level)
# Graphen zeichnen
old.pty <- par()$pty
par(pty="s", ask=T)
if (singleplot) layout(matrix(1:4,ncol=2))
for (i in 3:1) {
x <- seq(from=ranges[-i,][1,1],...