Displaying 1 result from an estimated 1 matches for "common_elements".
2011 Nov 04
1
Counting number of common elements between the rows of two different matrices
...1: 1 # (8 is a common element)
A1 vs B2: 1 # (8 is a common element)
A2 vs B1: 1 # (2 is a common element)
A2 vs B2: 1 # 11, 13 are common elements
Etc.
I've built a function that counts the number of common elements between
two vectors, based on the intersect function in the R manual
common_elements <- function(x,y) length(y[match(x,y,nomatch=0)])
And a double loop who solves my problem would be something like
(pseudo-code)
For(i in 1:N_A){
for(j in 1:N_B){
ce(i,j)=common_elements(a(i),b(j))
}
}
Is there an efficient, clean way to do the same job and give as an
output a matrix N_A...