search for: colums

e.g. a= a b c d e 1 1 1 3 1 1 2 1 2 3 4 5 3 1 3 3 8 3 4 1 4 3 3 5 5 1 1 3 1 1 I want to delete colume a and colume c, because they have the same values in every row, then ,I want to get this data.frame . b= b d e 1 1 1 1 2 2 4 5 3 3 8 3 4 4 3 5 5 1 1 1 the following is my code but it's wrong. rm(list=ls()) a=c(1,1,1,1,1); b=c(1,2,3,4,1); c=c(3,3,3,3,3);

Dear R experts: I have following data structure: student id, exam time and score. I want to create three new columes: 1 st before, 2nd before and 3rd before. For example, for student 1's 4th exam score is assumed to be influenced by his previous three cloest scores, which are 6, 9, and 10 in that order. For student 2's 5th exam score is assumed to be inflenced by her previous cloest

...%2Bfarver%2B2.jpeg So i want to pull out the data in coloured boxes it become organized like this (just in R instead of excel); http://www.nabble.com/file/p21667074/PRRS-billede%2Bexcel.jpeg So the 0'es and 1'es represent when either "PRRS-neg" occurs presented by a 0 in the colums PRRS-VAC and PRRS-DK on a particular date. And the same with "PRRS-pos VAC" or "Vac" presented by a 1 in the colum PRRS-VAC, and "PRRS-pos DK" or "DK" presented by a 1 in the colum PRRS-DK. And also with "sanVAC" there should be a 1 in the colum VA...

I do not understand some colums in the output to ''shorewall show connections'' /root> shorewall show connections Shorewall-2.0.2f Connections at firewall - Mon Jan 3 13:12:52 PST 2005 .. tcp 6 353296 ESTABLISHED src=112.129.244.121 dst=224.81.133.205 sport=3647 dport=443 src=224.81.133.205 dst=112.129.244...

Hi everybody How do I do to calculate the median and average of a colum of time data like this: "8:50:10". I also need to plot the time difference between two colums Thanks a lot -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932287.html Sent from the R help mailing list archive at Nabble.com.

Hello, can anybody tell me a easy way to change the mode of an "aggregate list" to "numeric"? I found a solution but I looks cruel. Thank's Felix PS: In the past you have asked what I am doing. I have to evaluate measures of two gauges of our university. The aim is to get an answer which one is better. > mode(MEAN) [1] "list" > mode(MEASURE) [1]

hello, this is my script: #1) read in data: daten<-read.table('K:/Analysen/STRUCTURE/input_STRUCTURE_tab_excl_5_282_559.txt', header=TRUE, sep="\t") daten<-as.matrix(daten) #2) create empty matrix: indxind<-matrix(nrow=617, ncol=617) indxind[1:20,1:19] #3) compare cells to each other, score: for (s in 3:34) { #walks though the matrix colum by colum, starting at

...erisk 1.8 from repo: https://wiki.asterisk.org/wiki/display/AST/Asterisk+Packages And Looked at this article about CDR in mysl. http://www.voip-info.org/wiki/view/Asterisk+cdr+mysql I installed asterisk-mysql pacakge from debian repo. The cdr in mysql is working, but i can not get cdr adaptive colums are not, i use this in my extension.conf exten => s,1,set(CDR(teste)=${CHANNEL(audioreadformat)}) And is not working, i thought the only diference it i would need the colum teste in my cdr table right ? I tryied a lot of combinations of exten => Does anyone have any ideia how is the right...

my programe is below: a=c(1,2,1,1,1); b=c(1,2,3,4,1); c=c(3,4,3,3,3); d=c(1,2,3,5,1); e=c(1,5,3,5,1) data.f=data.frame(a,b,c,d,e) origin.data<-data.f cor.matrix<-cor(origin.data) origin.cor<-cor.matrix m<-0 for(i in 1:(cor.matrix[1]-1)) { for(j in (i+1):(cor.matrix[2])) { if (cor.matrix[i,j]>=0.95) { data.f<-data.f[,-i]; i<-i+1 }

Hello, I have a problem with reading a csv-file. One colum of the inputfile consists of characters and numbers. After reading the csv-file I create a new dataframe by dividing the values of that colum into more colums (then a colum contains just characters or numbers) but the numbers are converted to factors. How can I create the new dataframe without having the numbers converted to factors? ----- Tamara Hoebinger University of Vienna -- View this message in context: http://www.nabble.com/convert-factors-to-nu...

Hi all: Can someone help me count the number of rows with values in colum "a" only. assume the name of my dataframe is "weekly" I was trying i<- nrows(weekly$a) i but returns 7 when it should be 4. Thanks a b c d 27.000 27.000 1.569 0.013 160.000 27.000 1.632 0.013 146.000 27.000 1.830 0.015 70.000 27.000 2.475 0.019

Hello, I've a data frame with 15 colums and 6000 rows, and I need the data in a single vector of size 90000 for ttest. Is there such a conversion function in R, or would I have to write my own loop over the colums? thanks for your help + kind regards Arne

Hi, Hopefully someone can point me in the right direction on how I would go about solving the following. I have some data and need to find the column name of the maximum value in each row. This could be the data... > a <- data.frame(x = rnorm(4), y = rnorm(4), z = rnorm(4)) > a x y z 1 1.6534561 0.11523404 0.2261730 2 -1.2274320 -0.24096054 1.5096028

hallo, i have a problem by writing a csv file the first colum is filled with index numbers from 1 to n. i have to unique two csv files once a week while one file is always the same. can anybody tell me, how to write the dataset into a csv file without the first row of the indexnumbers. x[,-1] does not wok as it eliminates the first "interesting" colum. col.names is not accepted by r

Hi You wrotte me in R help and I´m very gratefull. I couldn´t reply because an illness. I writte this to see if you can help to solve. I´m a begginer (I´m 20 years old ) but I´m trying to learn more about this program also I´m learning Octave. I need to create a matrix in R whose values depends on the values of other matrix. You see: I have a first "R" matrix whose first row and

Hello, I'm trying to set up the flowwing data structure in R: A data frame with 7,000 rows and 4 colums. The rownames have some special meaning (they are names of genes). The 1st column per row is itself a data frame, and columns 2 to 4 will keep numeric values. The data frame contained in the 1st column will have 54 rows (with special names) and 4 colums (1st col is a response, cols 2- 4 are factor...

Hey again, I didn't wat questions to get mangled up, so here's my second email. In matlab, there is the simple possibility to access colums x till last of a matrix using mydata(1:3, 5:end). In R, I so far use mydata[1:3, 5:ncol(mydata)] Is there a faster way? (in terms of typing) Thanks ahead, Berry ------------------------------------- Berry Boessenkool University of Potsdam, Germany -------------------------------------

...ter,7 Character,2 .................... Now i want to convert it in a table as above. how to do this? Thanks for your suggestion AKJ -- View this message in context: http://r.789695.n4.nabble.com/how-to-convert-list-of-matrix-raster-extract-o-p-to-data-table-with-additional-colums-polygon-Id-cla-tp4634579.html Sent from the R help mailing list archive at Nabble.com.

..., sep = ",", fill = TRUE) R treats rows as columns and columns as rows. Is there someway to change this bahaviour? Or can i post process the data once I read it in? Thanks a lot! -- View this message in context: http://www.nabble.com/How-to-best-read-in-this-data---Switching-rows-and-colums-tp16447071p16447071.html Sent from the R help mailing list archive at Nabble.com.

Hi All, I've the following data frame with 54 rows and 4 colums: > x Ratio Dose Time Batch R.010mM.04h.NEW 0.02 010mM 04h NEW R.010mM.04h.NEW.1 0.07 010mM 04h NEW ... R.010mM.24h.NEW.2 0.06 010mM 24h NEW R.010mM.04h.OLD 0.19 010mM 04h OLD ... R.010mM.04h.OLD.1 0.49 010mM 04h OLD R.100mM.24h.OLD...