search for: colnm

...w to do in C, for very large matrices: > (mymat <- matrix(c(1,0,0,2,2,1), nrow = 2)) [,1] [,2] [,3] [1,] 1 0 2 [2,] 0 2 1 And I would like to produce: [1] "a*C" "B*c" Which can be trivially done in R via something like: foo <- function(mymat, colnms, tilde = FALSE) { apply(mymat, 1, function(x) { if (tilde) { colnms[x == 1] <- paste0("~", colnms[x == 1]) } else { colnms[x == 1] <- tolower(colnms[x == 1]) } paste(colnms[x > 0], collapse = "*") }) } &g...

To do this in C, it would probably be easier and faster to just do the string manipulation directly. Luckily, there are already packages that have done this for you. See an example below using the S4Vectors package. foo2 <- function(mymat, colnms, tilde=FALSE) { chars <- colnms[col(mymat)] lowerChars <- if (tilde) paste0("~", chars) else tolower(chars) chars <- ifelse(mymat==1L, lowerChars, chars) keep <- mymat > 0L charList <- split(chars[keep], row(chars)[keep]) S4Vectors::unstrsplit(ch...

..."somewhatm", "verym", "somewhatc", "veryc", "somewhatl", "veryl", "village", "married", "social", "agricultural", "communist", "minority", "religious") colnms <- c("depression", "sleep", "female", "village", "agricultural", "married", "communist", "minority", "religious", "social", "no", "primary", "m...

Good Morning. Below I like statement like j<-grep(".r\\b",colnames(mydata),value=TRUE); j with the \\b option which I read long time ago which Ive found useful. Are there more or these options, other than ? grep? Thanks. dstat is just my own descriptive routine. > x ?[1] "age"????????? "sleep"??????? "primary"????? "middle" ?[5]

I have data.frame's with IDs and multiple columns. B/c some of IDs showed up more than once, I need sum up colum values to creat a new dataframe with unique ids. I hope there are some cheaper ways of doing it... Because the dataframe is huge, it takes almost an hour to do the task. Thanks so much in advance! Young # ------------------------- examples are here and sum.dup.r is at the

Hi, I have one of those questions that I suspect is very simple, but hard to classify, so I have been searching for quite some time and am not able to find it. If I have a data frame and I want to change all the values of one of the columns to blanks, what is the syntax? I tried a few different spellings of Null, etc., but can't get it. Can someone please send me what I suspect is a one

Hello, has someone written by chance a function to extract the variance-covariance matrix from a lmer-object? I've noticed the VarCorr function, but it gives unhandy output. Regards, Roel de Jong

Dear sir, I have a matrix like a<-matrix(c(0,2,0,4,0,6,5,8,0),nrow=3) colnames(a)<-c("F1","F2","F3") rownames(a)<-c("A1","A2","A3") a F1 F2 F3 A1 0 4 5 A2 2 0 8 A3 0 6 0 I want to extract all pairs (rownames, columnames) from which the value in the matrix is 0 The result should be something like this A1, F1 A2,

Hi, I am passing a data frame and field name to a function. I've figured out how I can create the formula based on the passed in field name, but I'm struggling to create a vector based in that field. for example if I hard code with the actual field name Y = df$Target, everything works fine. but if I use the passed in parameter name, it doesn't give me what I want, Y =

Your surest bet is to look into S+, not R, since the former does 'integrate' with Microsoft applications. To what extent, I don' know. This is a desirable feature (IMO) and a reason to use S+ rather then R (already discussed in different thread). Try the S+ newsgroup. > -----Original Message----- > From: r-help-bounces at stat.math.ethz.ch > [mailto:r-help-bounces at

I'm coming out with all the classic problems today ;-) Can anyone tell me how to change the column names of an already existing data frame? I've read the docs for ?data.frame and ?as.data.frame but can't figure it out. I want to make a new data.frame from some of the columns of an existing data.frame, but when I do that, the new data.frame columns have the same names as the old