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colmar
2008 Mar 05
3
ipf function in R
Hi
I have a 3 x 2 contingency table:
10 20
30 40
50 60
I want to update the frequencies to new marginal totals:
100 130
40 80 110
I want to use the ipf (iterative proportional fitting) function which
is apparently in the cat package.
Can somebody please advice me how to input this data and invoke ipf in R
to obtain an updated contingency table?
Thanks.
By the way I am quite new to R.
--
Dr
2012 Jul 27
2
How can I use IPF function correctly?
Hi All,
I am trying to creat a simple example byusing ipf function in R, but i
could not get it succefully...I am very new to R, does anyone could help,
to instruct me about this ipf fucntion?
Actually, this is what I mean
50 | 50
----------------------
33.4| 28.57 | 14.29
33.3| 23.81 | 4.762
33.3| 9.523 | 19.05