Displaying 3 results from an estimated 3 matches for "colf".
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2010 Jan 29
1
apply function with grouped columns
...5)
v3 <- c(3, 2, 9, 4)
v4 <- c(4, 1, 1, 1)
myData <- data.frame(v1=v1, v2=v2, v3=v3, v4=v4)
myData
#The observations have either property 1 or property 2
rowFactor <- data.frame(RowTraits=factor(c(1, 2, 1, 2)))
rowFactor
#The variables have a property that is either present or absent
colFactor <- data.frame(ColTraits=factor(c(1, 1, 0, 0)))
colFactor
#Getting the means for the columns by row groups is easy
MeanByRowTraits <- aggregate (myData, rowFactor[1], mean)
MeanByRowTraits
#But now to get the means for the rows by column groups is awkward
rotateData <- data.frame(t(M...
2015 Feb 24
2
intercalar elementos de vectores
...la
> tabla que tienes:
>
> > #Creo un data.frame de ejemplo todo con letras
> > vtmp <- as.data.frame(lapply(letters,function(x) { rep(x,each=50) }))
> > names(vtmp) <- paste("col",LETTERS,sep="")
> > head(vtmp)
> colA colB colC colD colE colF colG colH colI colJ colK colL colM colN
> colO colP colQ colR colS colT colU colV colW colX colY colZ
> 1 a b c d e f g h i j k l m n
> o p q r s t u v w x y z
> 2 a b c d e f g h i...
2015 Feb 24
2
intercalar elementos de vectores
Excelente! Ahora corre muy rápido. No conocía ese método, creo que me va a
resultar muy útil.
Muchas gracias y saludos.
Fernando Macedo
El 24/02/15 a las 10:51, Jorge I Velez escribió:
Fernando,
Podrias intentar
R> a <- rep('a', 5)
R> b <- rep('b', 5)
R> a
[1] "a" "a" "a" "a" "a"
R> b
[1] "b"