search for: col9

...ble. The file consists of 100 tables, each of which is headed by two lines of characters. The first of these lines is: TABLE NO. 1 The second is a list of column headers. For example: TABLE NO. 1 COL1 COL2 COL3 COL4 COL5 COL6 COL7 COL8 COL9 COL10 COL11 COL12 1.0010E+05 0.0000E+00 1.0000E+00 1.0000E+03 -1.0000E+00 1.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 1.0010E+05 1.0001E+01 1.0000E+00 1.0000E+03 -1.0000E+00 1.0000E+00 2.2737E-14 -2.2737E-14 0.0000E+00 1.9281E...

Dear useRs, i want to split a matrix having 1116rows and 12 columns. i want to split that matrix into 36 small matrices each having 12 columns and 31 rows. The big matrix should be splitted row wise. which means that the first small matrix should copy values which are in first 31 rows and 12 columns of the big matrix. similarly 2nd small matrix should contain values from 32nd to 63rd row of the

...number of values in each row of columns 6-10 that were NA??s (2) the sum of all values on columns 1-5 for which there were no missing values in the corresponding cells of columns 6-10. Example: (let??s call the data frame "data") Col1 Col2 Col3 Col4 Col5 Col6 Col7 Col8 Col9 Col10 1 2 5 2 3 NA 5 NA 1 4 3 1 4 5 2 6 NA 4 NA 1 The result would then be (for the first row) (1) "There were 2 NA??s in columns 6-10." (2) The mean of Columns 1-5 was 2+2+3=7" (because there we...

dear useRs, i have a list containing 16 matrices. i want to calculate the column mean of each of them. i tried >sr <- lapply(s,function(x) colMeans(x, na.rm=TRUE)) but i am getting the following error >Error in colMeans(x, na.rm = TRUE) : 'x' must be numeric can it be done in any other way? and why i am getting this error?? thanks in advance.. elisa [[alternative

...), "\n") #GB = 0.397 colnames(DF) = NULL system.time(nm1<-colnames(DF, FALSE)) # user system elapsed # 22.158 0.299 22.498 print(nm1) #[1] "col1" "col2" "col3" "col4" "col5" "col6" "col7" "col8" "col9" ### restart R colnames <- function (x, do.NULL = TRUE, prefix = "col") { if (is.data.frame(x)) { nm <- names(x) if (do.NULL || !is.null(nm)) return(nm) else return(paste0(prefix, seq_along(x))) } dn <- dimnames(x...

Hello, I'm using <read.csv("filename",header=TRUE) but need to extract just certain columns or rows from the file. Much thanks. -- View this message in context: http://n4.nabble.com/selecting-certain-columns-or-rows-from-a-csv-tp1835692p1835692.html Sent from the R help mailing list archive at Nabble.com.

Hi, is there a way I can calculate a summary statistics for a columns matrix let say we have this matrix x <- matrix(sample(1:8000),nrow=100) colnames(x)<- paste("Col",1:ncol(x),sep="") if I used summary summary(x) i get the output for each column but I need the output to be in matrix with rownames and all the columns beside it this how I want it

...> colnames(DF) = NULL > system.time(nm1<-colnames(DF, FALSE)) > # user system elapsed > # 22.158 0.299 22.498 > print(nm1) > #[1] "col1" "col2" "col3" "col4" "col5" "col6" "col7" "col8" "col9" > > ### restart R > > colnames <- function (x, do.NULL = TRUE, prefix = "col") > { > if (is.data.frame(x)) { > nm <- names(x) > if (do.NULL || !is.null(nm)) > return(nm) > else > return(paste0...

...w??? > > col1=rgb(0.164,0.043,0.850) # Set the colors > col2=rgb(0.150,0.306,1.000) > col3=rgb(0.250,0.630,1.000) > col4=rgb(0.450,0.853,1.000) > col5=rgb(0.670,0.973,1.000) > col6=rgb(0.880,1.000,1.000) > col7=rgb(1.000,1.000,0.750) > col8=rgb(1.000,0.880,0.600) > col9=rgb(1.000,0.679,0.450) > col10=rgb(0.970,0.430,0.370) > col11=rgb(0.850,0.150,0.196) > col12=rgb(0.650,0.000,0.130) > colTemperature=c(col1,col2,col3,col4,col5,col6,col7,col8,col9,col10,col11,col12) # Put all colors in a vector > > tempLT50_ACC=fieldTrial0809[idx, c(48)] > t...

...NA Col3 0.62603 NA NA NA Col4 0.27695 NA NA NA Col5 0.06056 NA NA NA Col6 -0.19582 NA NA NA Col7 -0.83044 NA NA NA Col8 -1.27914 NA NA NA Col9 -1.93235 NA NA NA Col10 -2.49709 NA NA NA When I omited 'weights=w' above table was filled in with numbers, but the results were wrong (because of taking zeros in regression). Could you tell me what's wrong? Kind regards, Robert

Hi, In a function, I compute 10 (un-named) vectors of reasonable length (4471 in the particular example I have to hand) that I want to combine into a data frame object, that the function will return. This is very slow, so *I'm* doing something wrong if I want it to be quick and efficient, though I'm not sure what the best way to do this would be. I know it is the combining into data

Hi, I'm still trying to figure out that GLM procedure in SAS. Let's start with the simple example: PROC GLM; MODEL col1 col3 col5 col7 col9 col11 col13 col15 col17 col19 col21 col23 =/nouni; repeated roi 6, ord 2/nom mean; TITLE 'ABDERUS lat ACC 300-500'; That's the same setup that I had in my last email. I have three factors: facSubj,facCond and facRoi. I had this pretty much figured out with three lengthy calls to lm(...

Hello, my question is about the data handling. I have a data set that is lined as: 4 1 17 1 1 -5.1536 -0.1668 -2.3412 -0.5062 0.9621 0.3640 0.3678 -0.5081 -0.2227 0.8142 -0.0389 -0.0445 -0.0578 -0.1175 -0.1232 0.8673 -0.1033 -0.0796 -0.0341 -0.1716 -0.1801 -0.7014 0.6578 0.5611 4 1 17 2 1 -5.1536 -0.1668 -2.3412 -0.5062 0.9621 0.3640 0.3678 -0.5081 -0.2227 0.8142 -0.0389 -0.0445

Hello, I just can''t seem to find a way to extend a form dynamically in ROR. Say I am writing a recipe website. There is one form to enter the recipe. There is room for N number of ingredients (let''s say a text field for each ingredient name and selection list for the amount). What if the user wants to add more than N ingredients as he types them in? how do I do this without