search for: coinciding

Buenas tardes, Quiero aplicar la función rbind y necesito tener los mismos nombres de columnas. Como tengo unas 195 variables en cada dataframe, necesito hacerlo de una forma rápida. Tengo 9 bases de datos y tengo que fusionar todas. ¿Como puedo comprobar que los nombres de las variables son los mismos? Y de lo contrario, ¿como detecto las diferencias? He probado con

Recent news articles concerning an article from The Lancet with fabricated data indicate that in the sample containing some 900 or so patients, more than 200 had the same birthday. I was curious and tried out the p and q birthday functions but pbirthday could not handle 250 coincidences with n = 1000. The calculation of upper prior to using uniroot produces NaN, upper<-min(n^k/(c^(k-1)),1)

I'm looking at algorithms for determining coincidences. In educational testing, it is interesting to look at cheating via the birthday problem where I can assess the probability of n students having the same test score in a class of size k. I was writing my own code for the b-day problem until I ran into the qbirthday() function, which has solutions for the overflow problems I kept running

Hi, I am trying to do a bayesian prediction for soil pollution data above a certain threshold, using geoR. Everything is working fine until i am doing the krig.bayes. I tried to do the prediction on a grid 67 by 113 cells and my computer is freezing to death. At larger numbers of cells it tells me after a while that it reaches the max. memory of 511 Mb. My computer has only 512 Mb of RAM.

Thank You. i used -polly-ast-detect-parallel but there is no coincident info generated; my c code is simple vec-sum as follows; #include <stdio.h> int a[2048], b[2048], c[2048]; foo () { int i; for (i=0; i<2048; i++) { a[i]=b[5] + c[i]; } } i executed following commands; $clang -S -emit-llvm vec-sum.cpp -march=native -O3 -mllvm -disable-llvm-optzns -o vec-sum.s $opt -S

http://www.theregister.co.uk/2009/10/22/win7_launch/ After you read the article, check out the comment about the timing of the CentOS 5.4 release and draw your own conclusions. ;> -- Ron Loftin reloftin at twcny.rr.com "God, root, what is difference ?" Piter from UserFriendly

Dear List, I registered for the useR conference in Rennes today; half an hour after the confirmation I received a first "requested newsletter" from a company selling a product named "Inference for R". This coincidence might be spurious. Or not, depending on frequency. Dieter

Hi all, I have this information on a file ht.txt, imagine it is a data frame without labels: 1 1 1 8 1 1 6 4 1 3 1 3 3 And on other table called "pru.txt" I have sequences similar this 4 1 1 8 1 1 6 4 1 3 1 3 3 1 6 1 8 1 1 6 4 1 3 1 3 3 1 1 1 8 1 1 6 4 1 3 1 3 3 6 6 6 8 1 1 6 4 1 3 1 3 3 I want to now how many positions are identical between each row in pru compared with ht. n and m

Klaas wrote: >> A reconnect that lasts less than one minute is counted as continuous outage. > Do you mean 'more than one minute?'. I didn't describe it fully. If an outage is detected, the system attempts a reconnect immediately. If a reconnect is established but is lost again without a full minute of audio, I don't log it as a reconnect. Once a reconnect is

Hi : I looked at the help for system.time but I still have the following question. Can someone explain the output following output of system.time : user system elapsed 12399.681 5632.352 56935.647 Here's my take based on the fact that I was doing ps -aux | grep R off and on and the total amount of CPU minutes that got allotted before the job ended was about 5 hours and the

Hi, pbirthday(, coincident = 2) starts to issue warnings (see (*) below) for larger number of classes (R 4.0.0, R-devel ./src/library/stats/R/birthday.R:47). The default coincident = 2 is computed as 1 - prod((c:(c - n + 1))/rep(c, n)) where c = classes. Using exp(log(...)), one can derive the return value if(n > 0) 1 - exp(sum(log1p(-(0:(n-1))/c))) else 0. Simplifying this a bit further one

# 2.0.11: /usr/local/etc/dovecot/dovecot.conf # OS: FreeBSD 8.2-STABLE amd64 Dovecot stops with the following logged: - master: Fatal: kevent(): Invalid argument I have found that a diff was created for "src/lib/ioloop-kqueue.c" for a similar issue: http://dovecot.org/pipermail/dovecot/2010-November/054855.html I have patched my system with this and haven't seen the problem

Full_Name: Andy Lynch Version: 1.9.1 OS: Windows Submission from: (NULL) (131.111.86.211) As I understand it, pbirthday(n,c,k) gives the approximate probability that we see a class with k coicident people in it when n people are sorted into c classes. so the command > pbirthday(4,classes=3,coincident=4) should give the approximate probability that when four people fall into three

...m=205 ?n=199 ?set.seed(7); ?a=matrix(rnorm(m*n), m, n) ?a[sample(seq(m*n), m*(n-4))]=0 ?a=as(a, "Matrix") ?qa=qr(a); ?stopifnot(nrow(qa at R) == m) ?# On my box I have nrow(qa at R):=207 while should be 205 as m is) Note that for m=203 and n=197, the same code produce right (i.e. coinciding) dimensions. Have I missed something? Serguei. > R.version platform?????? x86_64-pc-linux-gnu arch?????????? x86_64 os???????????? linux-gnu system???????? x86_64, linux-gnu status major????????? 3 minor????????? 4.3 year?????????? 2017 month????????? 11 day??????????? 30 svn rev??????? 7379...

When starting, for example, FreeCell in managed more, the program opens with the top of the window out of the top of my screen (i.e. the top corner of my desktop coincides with the top-left of the menu bar). It's not a huge problem, but I can't move the program... -- ------------------------------------------------- Richard Spandit Firmly on the Linux wagon SuSE 6.3, KDE 2.0

Hello. I have a problem with 2 dataframes. There are 2 columns - "value" and "dates". These dataframes have different dimension. Some dates coincide. And I need to intersect them by dates and have on output two dataframes with identical columns "dates" and new dimension . "value" have to recieve in compliance with dates. Regards, Aleksander. [[alternative

Hi All, is there any effiective and dense/compact method to calculate the mean of a list of - of course coincident - matrices on an element by element basis? The resulting matrix' [i, j]-th element is the mean of the list's matrices' [i, j]-th elements respectively... Iterating by for statement is quite straightforward, but I am seeking for a more elegant solution, and my attempt with

Dear Abby, > On Aug 30, 2019, at 8:20 PM, Abby Spurdle <spurdle.a at gmail.com> wrote: > >> I think that it would be better to handle factors, character predictors, and logical predictors consistently. > > "logical predictors" can be regarded as categorical or continuous (i.e. 0 or 1). > And the model matrix should be the same, either way. I think that

"Using FLAC binary : /Users/Marcus/flac/test/../src/flac/flac Original file size 441044 bytes. Compression level 1, file size 421393 bytes. Compression level 2, file size 421393 bytes. Compression level 3, file size 373613 bytes. Compression level 4, file size 369517 bytes. Compression level 5, file size 369517 bytes. Compression level 6, file size 369517 bytes. Compression

Folks, This is, umm, odd. Two, at least, and possibly a third over the weekend, of some older Dell 1950's, suddenly died shortly after being upgraded to 5.6. They're all about the same age, and it's not happening with other systems, but they claim a scsi abort, and the f/s goes read-only. The little lcd screen goes orange, and shows a fatal error E 171, and B0 F3 D0? D0 F3