Displaying 4 results from an estimated 4 matches for "cnty".
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2005 Jul 04
2
Lack of independence in anova()
If the observations are normally distributed and the 2xk design is
balanced, theory requires that the tests for interaction and row effects be
independent. In my program, appended below, this would translate to cntT
(approx)= cntR*cntI/N if all R routines were functioning correctly. They
aren't.
sim2=function(size,N,p){
cntR=0
cntC=0
cntI=0
cntT=0
cntP=0
for(i in 1:N){
2011 Aug 31
1
looping by grouping variable
...Thus, I was able to extract a state variable, for which, I
want to use the averages, calculated at the state level, and utilize those
averages for another variable. I know this may be confusing, so I'm posting
an example dataset here:
id.tmp1<-as.character(01001:01010)
st<-substr(id,1,1)
cnty<-substr(id,2,5)
tfr10<-rnorn(1:10)
mydata<-cbind(id,st,cnty,tfr10)
print(mydata)
id st cnty tfr10
[1,] "1001" "1" "001" "1.07505442756833"
[2,] "1002" "1" "002" "-0.882434417011687&quo...
2008 Jul 31
1
Rearranging Data
...ce changes.
However, a new set of data I have is no longer in the same format.
CDSmod is the file that was used with this code:
x <- read.csv('/cdsmod.csv', as.is=TRUE, check.names=FALSE)
x$Date <- as.Date(x$Date, "%m/%d/%Y")
require(zoo)
out <- lapply(x[-1], function(.cnty){ # iterate for each country
# create a dataframe of the date and currency
.df <- data.frame(date=x[[1]], cur=.cnty)
.df <- .df[order(.df$date),] # sort in date order
.df$cur <- na.locf(.df$cur, na.rm=FALSE) # carry forward missing values
.df <- .df[complete.case...
2006 Jun 08
1
FW: asterisk and nortel meredian option 11c
Hi
I want to connect asterisk 1.0.9 ( kernel 2.6.8-2 debian )with TE110P
and Nortel meridian option 11c release 25.40 with NTBK50AA card which is
An E1 card. But the main problem is the first stage that no sync occurs
the * card never syncs with meridian card
I am using euroisdn, ccs , hdb3, crc4 , pri_net on asterisk
And I am assuming that meridian is using same as it is