search for: classnumber

Displaying 3 results from an estimated 3 matches for "classnumber".

2008 May 30
1
existing package (mmlcr) modification -- appropriate process?
...utput of multinom is the standard errors, but this output is not provided within mmlcr. I would like to obtain the standard errors as an output of mmlcr. For your reference, this is relevant code that I identified in mmlcr, using getAnywhere{mmlcrfit.multinomlong}: function (object, weights, classnumber) { data <- object$data form.full <- formula(attr(data, "terms")) form <- object$shortform data$.wts <- weights[match(getGroups(data, form.full, 1), row.names(weights)), classnumber] component.multinom.result <- multinom(form, data = data,...
2006 Oct 25
2
update index in "for" statement during calculation
...ady, Kim ### Code ### for (i in 1:(nrow(data)-1)) { diff.time <- round(data[i+1,2], 0) - round(data[i,2], 0)-1 old.row <- nrow(data) if (diff.time > 0) { fill <- c(data[i,1], (round(data[i,2], 0)+1), rep(0,classnumber)) data <- rbind(data[1:i,], fill, data[(i+1):old.row,]) } } __________________________________________ Kim Milferstedt University of Illinois at Urbana-Champaign Department of Civil and Environmental Engineering 4125 Newmark Civil Engineering Laboratory 20...
2013 Feb 17
6
histogram
...49 37 50 45 1. i first of all want to make classes in the following form class 0<x<=5 5<x<=10 10<x<=15 15<x<=20 ..... ... ... ... 45<x<=50 and then i want to count the number of elements in each class and?ultimately?i want to execute a table in the following form classnumber of elements in each class 0<x<=55 5<x<=105 10<x<=155 15<x<=205 ..... ... ... ... 45<x<=505 the command which i used is to count the number of elements in each class was > length(which(x > 45 & x <= 50)) 2. is there a loop command which can count the nu...