Displaying 6 results from an estimated 6 matches for "citycode".
2018 Mar 25
3
Take average of previous weeks
Dear all,
I have weekly data by city (variable citycode). I would like to take the
average of the previous two, three, four weeks (without the current week)
of the variable called value.
This is what I have tried to compute the average of the two previous weeks;
df = df %>%
mutate(value.lag1 = lag(value, n = 1)) %>%
mutate(value .2.previous...
2016 Apr 20
1
Use multiple cores on Linux
...ly show two).
Is it possible to run this code using HPC packages such as
Rmpi/snow/doParallel? Thank you!
#####################
library(data.table)
library(mgcv)
library(reshape2)
library(dplyr)
library(tidyr)
library(lubridate)
library(DataCombine)
#
gam_max_count_wk <- gam(count_pop ~ factor(citycode) + factor(year) +
factor(week) + s(lnincome) + s(tmax) +
s(hmax),data=cont,na.action="na.omit", method="ML")
#
# Historic
temp_hist <- read.csv("/work/sd00815/giss_historic/giss_temp_hist.csv")
humid_hist <- read.csv("/work/sd00815/giss_historic/giss_hum_hi...
2018 Mar 25
0
Take average of previous weeks
...open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sun, Mar 25, 2018 at 7:48 AM, Miluji Sb <milujisb at gmail.com> wrote:
> Dear all,
>
> I have weekly data by city (variable citycode). I would like to take the
> average of the previous two, three, four weeks (without the current week)
> of the variable called value.
>
> This is what I have tried to compute the average of the two previous weeks;
>
> df = df %>%
> mutate(value.lag1 = lag(value, n = 1)) %...
2018 Mar 26
1
Take average of previous weeks
...along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Sun, Mar 25, 2018 at 7:48 AM, Miluji Sb <milujisb at gmail.com> wrote:
> > Dear all,
> >
> > I have weekly data by city (variable citycode). I would like to take the
> > average of the previous two, three, four weeks (without the current week)
> > of the variable called value.
> >
> > This is what I have tried to compute the average of the two previous
> weeks;
> >
> > df = df %>%
> >...
2001 Nov 27
3
Equations as arguments to functions
...t;- eq}
a _ rnorm(100)
go(10,eq=a[.5*length(a)]+C+1)
> C
[1] 20
> d
[1] 21.10551
> a[.5*length(a)]
[1] 0.1055086
Everything looks good - (BTW seems like a really powerful feature of R)
Now on to my code of interest, which doesn't work (shown below).
rm(list=ls())
load("datasets/citycodes")
increments _ seq(5000,100000,by=5000)
makeindex <- function(Y,eq) {
losers _ 0; levels_0
index _ 0; location _ 0; cutoff _0; totalapt_0; houses_0
for (C in city[1:2]) {
counter _ 0
if (file.exists(paste("datasets/2000income/",C,sep=""))) {
load(paste("d...
2006 Jan 27
3
OT?: International number parsing
Can anyone shed some light on "rules" that might make the task of
parsing the country code and city codes from a dialed number in the
CDRs?
I know that there is almost never a case where a concatenated country
and city code could overlap with another country code, but what about
city codes and local numbers? Is it possible for a concatenated city
code and local number to match another