search for: chuva

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2012 Oct 19
1
multiple graphs, lapply and different titles
I have a list of data.frames, and i want to iterate over this list and generate graphs with the same title of the data.frame. I did the graphs with: lapply(anual, function(x) plot(x[,'chuva'], type='l', xlab= 'anos', ylab = 'Precicipatação(mm)', col='red')) where anual is list of data.frames. I am plotting just the column "chuva" at each data.frame. How can i do that? -- Att, Flávio Barros [[alternative HTML version deleted]]
2012 Aug 10
5
help error histograma
Hi, My error isErro em hist.default(dados[[1]], freq = TRUE, seq(0, 30, 0.5), prob = FALSE, : some 'x' not counted; maybe 'breaks' do not span range of 'x' hist(dados[[1]],seq(0, 30, 0.5), prob=TRUE, xlab="chuva (mm/dia)",ylab="frequência", main="", cex.lab=1.6, cex.sub=3,cex.axis=3,cex.main=6) Someone help me? [[alternative HTML version deleted]]
2012 Aug 09
1
help hist some 'x' not counted; maybe 'breaks' do not span range of 'x'
...uys, I would like help in script R when I try to plot the histogram appears the error: Erro em hist.default some 'x' not counted; maybe 'breaks' do not span range of 'x' I using a file with more 1000 datas (vector) hist(dados[[1]], seq(0, 20, 0.5), prob=TRUE, xlab="chuva (mm/dia)",ylab="frequência", main="", cex.lab=1.6, cex.sub=3,cex.axis=3,cex.main=6) Please, someone could help me? Thanks Best Regards [[alternative HTML version deleted]]