search for: chris82

Hi R users, is there any possibilty that a while loop is working like that: z <- c(0,1,2,3,4,5,6,7,8,9) r <- 7 while(w == T) { for ( i in 1:10 ){ w <- r == z[i] print(w) } } The loop should stop if w == TRUE best regards -- View this message in context:

Hello R-users, I have a little problem. I compare each row of a matrix with each row of another matrix. testmat1 <- matrix(c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16), nrow=4) testmat2 <- matrix(c(1,2,3,5,5,6,7,8,9,10,11,12,13,14,15,16), nrow=4) Both matrix differs in the last row. Now I create a loop: for (i in (1:4)){ for (j in (1:4)){ b <- (c(setequal(testmat1[j,],testmat2[i,])))

Hello R users, I want to readout the row and column postion from a certain matrix value into a csv file. I have only found this syntax "which(a == b, arr.ind = T)" so I get a = matrix [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 1 1 2 2 2 1 1 2 [2,] 1 2 3 3 3 4 4 3 [3,] 3 3 3 5 5 6 5 4 [4,] 4 4 4 3

hello R users, I didn't find a solution for a simple problem I think. I read 224 lines from a file input <- readLines(con,n=224) and now I create a string x <- "\004" which should be line 225 of input. So I have input and x and want to add x to input, so that it looks like this: [1] "string" [2] "string" . . . [224] "string" [225]

Hi R users, I want to colored points by their value for example: x <- c(1,2,3,4) y <- c(1,2,3,4) z <- c(2,3,4,9) y and x are coordinates z is the value of the coordinates points(x,y,col= rainbow(z)) something like that But haven't found any solution at the moment. Thanks. Chris -- View this message in context:

Hello R users, I have a little problem with a for loop. Below there is an simple example of my problem. I want to delet the commas in the character string. Fore this reason I create a for loop to unpick the string and rebuild him without the commas. The problem is, that "paste" does not work in the loop as I expected. text <- "aaa,bbb,ccc,ddd" characterseq <-

Hi R users, I have mentioned that R is getting slower if a process with a loop runs for a while. Is that normal? Let's say, I have a code which produce an output file after one loop run. Now after 10, 15 or 20 loop runs the time between the created files is stongly increasing. Is there maybe any data which fill some memory? Chris -- View this message in context:

Dear R users, I guess, I have a quit simple problem, but I'm not getting the solution. I create a matrix like this: test <- matrix(seq(1,3,1),ncol=5,nrow=3) then I want to create one vector, consisting of every row of the matrix. My first idea was to do this with a for loop. op <- vector() for (o in 1:3){ op[o] <- as.vector(test.id[o,]) } The results should be like this: [1]

hello R users, I didn't find a solution for a special problem. I have two dataframes. dataframe1: X value row col ID 1 8.973498062 5512625 3460000 1 2 11.656658570 5501625 3464000 2 3 11.121777570 5495625 3473000 3 4 9.310465964 5508625 3477000 4 5 8.883483845 5515625 3496000 5 dataframe2: X value

Hello R users, is there a possibility to get the relativ maximum of a matrix? To get the absolut maximum I use max(matrix) For example: The absolut maximum of this matrix is 6[3,6], but the relativ maximum is 6[3,6] and 4[7,6], because both values are the highest value in comparison to their eight neighbours values. [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 1 1 2 2 2

Hi R users, I have a maybe strange problem. Normaly I do image.plot() with x,y coordinates and add=T and if I have some NA values in my data matrix z, the color will be transparent of these pixels. But now I have a disorted coordinate system and x,y are a matrix. It works also fine, but now NA values are white colored and not transparent anymore. It is problematic if I have a secondary

Hello, I have a problem to flip a 200x200 matrix, which is imported by a .asc file. I want to flip the matrix like in a created example below: > b <- matrix(1:9,3,3,byrow=T) > b [,1] [,2] [,3] [1,] 1 2 3 [2,] 4 5 6 [3,] 7 8 9 > b1 <- apply(t(b),1,rev) > b1 [,1] [,2] [,3] [1,] 7 8 9 [2,] 4 5 6 [3,] 1 2 3 but my

Hi R users, I have a maybe small problem which I cannot solve by myself. I want to convert "chron" "dates" "times" (04/30/06 11:35:00) to a number with as.POSIXct. The Problem is that I can't choose different timezones. I always get "CEST" and not "UTC" what I need. date = as.POSIXct(y,tz="UTC") "2006-04-30 11:35:00

Hi, I'm searching for a function to subistute Values in a Matrix to new Values. For example: old value new value 1.1 6 1.2 7 . . . . . . 1.9 14 2.0 15 and 2.1 15.5 2.2 16 . . . . 2.9 19.5 3.0 20 There is a difference

...for specific values from > multiple .txt-files (Rui Barradas) > 4. Re: How to use external image with R plot? (Michael Sumner) > 5. Re: is it possible to insert a figure into into another new > figure by r script (Thomas Adams) > 6. image.plot transparent? (Chris82) > 7. Re: How to add marker in Stacked bar plot? (Jorge I Velez) > 8. Re: Predicted values for zero-inflated Poisson (Laura Lee) > 9. Re: how can I show the xlab and ylab information while using > layout (Sarah Goslee) > 10. Re: image.plot transparent? (Sarah Go...