Displaying 13 results from an estimated 13 matches for "chla".
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2005 May 25
1
question: corCAR1 in lme
Hello all,
I am trying to use lme to examine how a response variable (Chla) changes
over time in different treatments (2 Temp & 2 Light levels). Within each
treatment combination, there are two replicate tanks (each with unique
TankID) with coral fragments in them. All tanks are subject to the same
environment until Time=0, when treatments are imposed, and Chla...
2005 Jul 28
1
conversion from SAS
Hi, I wonder if anybody could help me in converting
this easy SAS program into R.
(I'm still trying to do that!)
PROC IMPORT OUT= WORK.CHLA_italian
DATAFILE= "C:\Documents and
Settings\carleal\My
Documents\REBECCA\stat\sas\All&nutrients.xls"
DBMS=EXCEL2000 REPLACE;
GETNAMES=YES;
RUN;
data chla_italian;
set chla_italian;
year=year(datepart(date));
month=month(datepart(date));
run;...
2007 Oct 23
1
Multivariate regression tree: problems with surrogate splits
R helpers,
I am working with the R program performing multivariate regression trees (MRT). I have a matrix with species and environmental variables saved as a CSV file (sprot_matrix.csv), I have 42 species and 8 environmental variables (SECCHI+PH+TA+PTOT+NTOT+CHLA+AREA+ MEANDEP) for 104 samples
Title
SpA
SpB
SpC
SpD
Varible1
Variable2
Variable3
Sample1
Sample 2
Sample 3
Sample 4
Sample 5...
2011 Oct 09
1
sapply(pred,cor,y=resp)
...obs. of 13 variables:
$ mnO2: num 9.8 8 11.4 4.8 9 13.1 10.3 10.6 3.4 9.9 ...
$ Cl : num 60.8 57.8 40 77.4 55.4 ...
$ NO3 : num 6.24 1.29 5.33 2.3 10.42 ...
$ NH4 : num 578 370 346.7 98.2 233.7 ...
$ oPO4: num 105 428.8 125.7 61.2 58.2 ...
$ PO4 : num 170 558.8 187.1 138.7 97.6 ...
$ Chla: num 50 1.3 15.6 1.4 10.5 ...
$ a1 : num 0 1.4 3.3 3.1 9.2 15.1 2.4 18.2 25.4 17 ...
$ a2 : num 0 7.6 53.6 41 2.9 14.6 1.2 1.6 5.4 0 ...
$ a3 : num 0 4.8 1.9 18.9 7.5 1.4 3.2 0 2.5 0 ...
$ a4 : num 0 1.9 0 0 0 0 3.9 0 0 2.9 ...
$ a5 : num 34.2 6.7 0 1.4 7.5 22.5 5.8 5.5 0 0 ...
$ a...
2007 Nov 02
1
lme model with replicates within a random factor
...s, I have tried an lme model with “time” and
“basin” as random factors. I have put hydrological cycle as a fixed factor,
since I’m interested in quantifying their effect. But I’m not sure if there
are other possibilities to do this.
This is my model structure:
Model1<-lme(shannon<-log(chla+1)*hyd_cycle+toc*hyd_cycle,
random=~time|basin)
Note that I have not put “replicate” within the random structure
(random=~time|basin/replicate), and this is my major concern. I’m not sure
if I have to include “replicate” in the random structure, since replicates
are randomly taken each time, an...
2007 Oct 03
0
datasets
...uis, and I have a problem with a dataset.
Its name is algae and count the collection of data in a lake and respective
proliferation of algae.
The parameters that it has are: "mxPH", "mnO2", "Cl", "NO3" "NH4", "oPO4",
"PO4", "Chla" and "a1" all numerics.
a1 - algae1
If I try to do SVM with him, it doesn't generate a square matrix, why?
If I try to do same thing in another dataset as Glass of the package
"mlbench"
with the data(Glass) that has the parameters:
"RI", "Na", &quo...
2008 Dec 08
1
partial correlation
...s the partial correlation between two variables given a set
of other variables) but I do not know how to change to a Spearman Rank
Correlation method [pcor(c("BCDNA","ImProd","A365"),var(PCor))]
Here''s a glimpse of my data (data is raw data).
A436
A365
Chla
ImProd
BCDNA
0.001
0.003
0.624889
11.73023
0.776919
0.138
0.126
0.624889
27.29432
0.357468
0.075
0.056
0.624889
105.3115
0.429785
0.009
0.008
0.312444
55.2929
0.547752
0.005
0.002
0.624889
26.9638
0.738775
0.018
0.006
0.312444
31.14836
0.705814
0.02
0.018
2...
2013 Nov 20
1
nlme function summary.lmList cannot be found with new versions
Hello,
I installed the newest version of R (3.0.2) as well as the newest version of
nlme (3.1-113) in order to use summary.lmList and other nlme functions. Once
loading the new library, lmList and summary.lm can be found, but a number of
additional functions cannot be found via command.
Versions installed and loaded are correct. Any suggestions on how to allow
for these functions of the new
2011 May 16
1
Linear Discriminant Analysis error: "Variables appear constant"
...m+FishIBIUsed
+QHEI+QHEIsub+QHEImwh_h+QHEIcov+QHEIchan+QHEIrip+QHEIpool+QHEIrif+QHEIgrads+
QHEIgradv+QHEImwh+QHEIcovtype+QHEIwwh+QHab+QHabBuff+QHabEros+QhabPool+
QHabWDRatio+QHabRif+QHabFines+QHabCov+QHabRating+QHabSize+TP+TKN+NH3+NH3Min
+NO3NO2N+BOD+TSS+TSSMax+TDS+SSC+SSCMax+Chloride+Sulfate+Ecoli+ChlA+DOper+
DOperMin+DOperMin1_5+DOmgL+DOmgLMean+DOmgLMax+Cond+pH+pHMax+Trans+Temp+
TempMin+Temp4+Crop100+Crop500+CropSub+Dev100+Dev500+DevSub+For100+For500+
ForSub+Pas100+Pas500+PasSub+Wat100+Wat500+WatSub+Wet100+Wet500+WetSub+
Undev100+Undev500+UndevTotal+Undev100NoPas+Undev500NoPas+UndevTotNoPas,
dat...
2006 May 17
1
Fix for augPred/gsummary problem (nlme library)
...after the colon.] Remove these, or change them, using, e.g.:
class(obj$DateTime) <- NULL
class(obj$AnyVariable) <- 'numeric' ## leaves the actual labels/units intact so that you can later restore them.
2) Execute your lme() statement &c on the object, e.g.:
test.1 <- lme(Chla ~ PO4, random=~1|Site, data=obj) ## or simply: lme(obj)
augPred(test.1)
plot(augPred(test.1))
(Note that if you are using a data.frame() as your data object you will need to supply a 'primary' statement to augPred(), e.g. augPred(test.1, primary=~PO4).
Regards,
Mark Difford.
--------...
2012 Jul 30
1
te( ) interactions and AIC model selection with GAM
...re
zooplankton biomass (bm) is the dependent variable and the continuous
explanatory variables are:
-time in Julian days (t), to creat a long-term linear trend
-Julian days of the year (t_year) to create an annual cycle
- Mean temperature of Winter (temp_W), Temperature of September (temp_sept)
or Chla.
Questions:
1) To introduce a tensor product modifying the annual cycle in my model, I
tried 2 different approaches:
- a) gam ( bm ~ t + te (t_year, temp_W, temp_sept, k = c( 5,30), d= ( 1,2),
bs = c( ?cc?,?cr?)), data = data)
-b) gam ( bm ~ t + te (t_year, temp_W, temp_sept, k = 5, bs = c(
?cc?,?c...
2007 Sep 05
3
'singular gradient matrix’ when using nls() and how to make the program skip nls( ) and run on
Dear friends.
I use nls() and encounter the following puzzling problem:
I have a function f(a,b,c,x), I have a data vector of x and a vectory y of
realized value of f.
Case1
I tried to estimate c with (a=0.3, b=0.5) fixed:
nls(y~f(a,b,c,x), control=list(maxiter = 100000, minFactor=0.5
^2048),start=list(c=0.5)).
The error message is: "number of iterations exceeded maximum of
2012 Jul 09
3
Predicted values for zero-inflated Poisson
Hi all-
I fit a zero-inflated Poisson model to model bycatch rates using an offset term for effort. I need to apply the fitted model to a datasets of varying levels of effort to predict the associated levels of bycatch. I am seeking assistance as to the correct way to code this.
Thanks in advance!
Laura
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