Displaying 1 result from an estimated 1 matches for "child_sex".
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child_idx
2010 Jun 04
2
using string as variable name in model
...zSS_WJ_AP
17 17 zSS_WJ_MF
What I'm trying to do is
varnames[1,2] -> outcome
lm(outcome ~ income + covariate1 + coviarate2, data=my.data) -> model
I get the following error message:
"Error in model.frame.default(formula = outcome ~ Hollings_Enroll + Child_sex + :
variable lengths differ (found for 'Hollings_Enroll')"
But when I run the model:
lm(zCANTAB_log_IED_totaltrials ~ income + covariate1 + coviarate2, data=my.data) -> model
it works fine. Eventually, once I resolve this, I'd like to make a custom R function to automatica...