Displaying 3 results from an estimated 3 matches for "check_u_0__kd_1_2015".
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check_u_0__kd_1_2011
2016 Apr 28
4
Interdependencies of variable types, logical expressions and NA
...)
+
+ }
Creating Check_U_0__Kd_1_2011 from Umsatz_2011 and Kunde01_2011
Creating Check_U_0__Kd_1_2012 from Umsatz_2012 and Kunde01_2012
Creating Check_U_0__Kd_1_2013 from Umsatz_2013 and Kunde01_2013
Creating Check_U_0__Kd_1_2014 from Umsatz_2014 and Kunde01_2014
Creating Check_U_0__Kd_1_2015 from Umsatz_2015 and Kunde01_2015
>
> table(Kunden01$Check_U_0__Kd_1_2011, useNA = "ifany")
Check 0 OK <NA>
1 16 13
> table(Kunden01$Check_U_0__Kd_1_2012, useNA = "ifany")
Check 0 OK <NA>
1 17 12
> t...
2016 Apr 28
0
Interdependencies of variable types, logical expressions and NA
...> + }
> Creating Check_U_0__Kd_1_2011 from Umsatz_2011 and Kunde01_2011
> Creating Check_U_0__Kd_1_2012 from Umsatz_2012 and Kunde01_2012
> Creating Check_U_0__Kd_1_2013 from Umsatz_2013 and Kunde01_2013
> Creating Check_U_0__Kd_1_2014 from Umsatz_2014 and Kunde01_2014
> Creating Check_U_0__Kd_1_2015 from Umsatz_2015 and Kunde01_2015
> >
> > table(Kunden01$Check_U_0__Kd_1_2011, useNA = "ifany")
>
> Check 0 OK <NA>
> 1 16 13
> > table(Kunden01$Check_U_0__Kd_1_2012, useNA = "ifany")
>
> Check 0 OK <NA>...
2016 Apr 28
0
Antwort: RE: Interdependencies of variable types, logical expressions and NA
...2011 from Umsatz_2011 and Kunde01_2011
> > > Creating Check_U_0__Kd_1_2012 from Umsatz_2012 and Kunde01_2012
> > > Creating Check_U_0__Kd_1_2013 from Umsatz_2013 and Kunde01_2013
> > > Creating Check_U_0__Kd_1_2014 from Umsatz_2014 and Kunde01_2014
> > > Creating Check_U_0__Kd_1_2015 from Umsatz_2015 and Kunde01_2015
> > > >
> > > > table(Kunden01$Check_U_0__Kd_1_2011, useNA = "ifany")
> > >
> > > Check 0 OK <NA>
> > > 1 16 13
> > > > table(Kunden01$Check_U_0__Kd_1_2012, useNA...