search for: chartodate

...In max(i) : kein nicht-fehlendes Argument f?r max; gebe -Inf zur?ck Can someone please please tell me what I am doing wrong? I guess it is something very simple and I'm just stupid here. Thank you guys very much!!! Marco -- View this message in context: http://r.789695.n4.nabble.com/Error-in-charToDate-x-tp4287158p4287158.html Sent from the R help mailing list archive at Nabble.com.

...2 [1] "Qty" > class(dsort$Date) #checked data type of column "Date" and it came back as a factor [1] "factor" > Date2=as.Date(dsort$Date) #attempt at changing the data type from a factor to a date object (see error below). Error in charToDate(x) : character string is not in a standard unambiguous format Dates in my table are listed in "3/4/2007" format. StatBat2 [[alternative HTML version deleted]]

Hello I have a huge file (not an R-file) in which the first column is a string with date, hour, minutes and seconds (For instance, "31-Jul-2010 23:59:00"). I tried as.Date but the error msg was "Error in charToDate(x) : character string is not in a standard unambiguous format". I have checked the help for the function as well as date but to no avail. How can that sort of string be transformed to something useful in R? Many thanks Ed

...1st Qu.: 1.000 15063.0: 15 18 : 82 Median : 2.000 15082.0: 15 19 : 79 Mean : 4.195 15125.0: 15 20 : 76 3rd Qu.: 7.000 15044.0: 14 7 : 75 Max. :20.000 (Other):762 (Other):377 > thedate <- as.Date(df.final$Date) Error in charToDate(x) : character string is not in a standard unambiguous format > -- View this message in context: http://r.789695.n4.nabble.com/SQL-Changing-Data-Type-tp3623508p3623508.html Sent from the R help mailing list archive at Nabble.com.

...still struggling a bit to read a .txt file with a date vector. My code is as below: data<-read.table(file.choose(),header=TRUE,sep="\t",dec=",",colClasses=c("Date","numeric","numeric","numeric")) But I am getting an error: Error in charToDate(x) : character string is not in a standard unambiguous format because my date vector is in a format below: format="%d.%m.%Y" But how can i define the date format for date vector in read.table function....? Br, Jack [[alternative HTML version deleted]]

...that R will read?the incorrectly entered date "11/23/21931" without producing a warning or an?error message at least under some circumstances. ? > as.Date("11/23/21931", format = "%m/%d/%Y") [1] "2193-11-23" > as.Date("21931-11-23") Error in charToDate(x) : character string is not in a standard unambiguous format Similarly, under some circumstances, R will convert an impossible date like February 31, 2011 to NA rather than issuing a warning. > as.Date("02/31/2011", format = "%m/%d/%Y") [1] NA > as.Date("2011-0...

...: $ Date : Factor w/ 510 levels "Apr 28, 1972",..: 98 178 134 311 13 342 268 228 55 481 ... $ index: Factor w/ 510 levels "100","1,000.302",..: 1 499 493 488 444 412 418 434 441 448 ... > msci$Date <-as.Date(msci$Date, dateFormat='%b %d, %Y') Error in charToDate(x) : character string is not in a standard unambiguous format -- View this message in context: http://r.789695.n4.nabble.com/factor-coercion-with-read-csv-or-read-table-tp4632622.html Sent from the R help mailing list archive at Nabble.com.

...er of stat() system calls to /etc/timezone was limiting how many scripts could be run effectively. I traced the problem to as.Date.character where strptime() is called without a timezone argument when there is no format argument. as.Date.character <- function(x, format="", ...) { charToDate <- function(x) { xx <- x[1L] if(is.na(xx)) { j <- 1L while(is.na(xx) && (j <- j+1L) <= length(x)) xx <- x[j] if(is.na(xx)) f <- "%Y-%m-%d" # all NAs } if(is.na(xx) || !is.na(strptim...

...ot;] - leafbiom97$LeafBiog[leafbiom97$Date == "i-1"]+ Litterfall_Ahmed97$littperiod[Litterfall_Ahmed97$Date =="i"])/ (sum(GPP_Ahmed13$GPP[GPP_Ahmed13$Date >= "i-1" & GPP_Ahmed13$Date <= "i"])/2) } #Error in charToDate(x) : Thanks for your help Ahmed Attia, Ph.D. Agronomist & Soil Scientist

...to behave like example 6 below as.Date(x = '1',format = '%j', origin= '2015-01-01') #[1] "2018-01-01" # example 5 # right, documented. x of class 'character' needs argument 'format' as.Date(x = '1', origin= '2015-01-01') #Error in charToDate(x) : # string de caracteres n?o ? um formato padr?o n?o amb?guo # example 6 # the safe way, the only one that outputs the right date as.Date(x = '1', format = '%j', origin= as.Date('2015-01-01')) #[1] "2018-01-01" sessionInfo() R version 3.4.4 (2018-03-15) P...

Hello - I have a csv file with a few date columns. Some of the records have an "NA" character string instead of the date. When I attempt to use read.csv() and typecast the columns using colClasses, I receive the following error: Error in charToDate(x) : character string is not in a standard unambiguous format Similarly, the following command produces the same error: as.Date("NA") However, as.Date(NA) performs as documented. Can we enhance the as.Date() function to convert "NA" strings into NA value prior to ty...

I have been having trouble passing a default argument to base::as.Date.character and think it is due to some funkiness in the function definition. base::as.Date.character is defined as function (x, format = "", ...) { # stuff deleted res <- if (missing(format)) charToDate(x) else strptime(x, format, tz = "GMT") as.Date(res) } which gives unexpected behaviour when passing a default value of "" for format. I think the check "if(missing(format))" should really be "if(format=="")". Defining the wrapper: as.Dat...

Hello I am new to R and I need to convert some dates (numeric format by matlab) to actual dates in R. For instance, Matlab -> 730456 -> >> datestr(730456) ans = 02-Dec-1999 R - > library(zoo) > as.Date(730456) [1] "3969-12-03" I don't not mind the output format but it needs to be right. Many thanks Ed

Hi, I am not sure I understand your question correctly. dat1<- read.table(text=" id??????????? responsed_at???????????????? number_of_connection????????????????? scores 1????????????????? 12-01-2010?????????????????????????????????? 1????????????????????????????????????????????? 2 1????????????????? 15-02-2010??????????????????????????????????