search for: chanderbio

Displaying 5 results from an estimated 5 matches for "chanderbio".

2012 Oct 25
3
problem in finding sizes of objects using a for loop
Dear All, I wanted to extract the sizes of all created objects. For E.g when I created 2 objects(x and y), I got their sizes using the following code: > x<-rnorm(10000) > y<-runif(100,min=40,max=1000) > ls() [1] "x" "y" > object.size(x) 80024 bytes > object.size(y) 824 bytes However, I was unable to get their sizes when I used a for loop in the following
2012 Oct 08
3
turn list into dataframe
Dear R users, I'm starting to use 'apply' functions rather than for loops in R, and sometimes the output is a bit different than what I want. In this case, the command was tapply(myvector,myindex,cumsum) And the output was something like this: $`SNRL1 Core 120` [1] 2.8546 4.0778 5.2983 6.3863 7.5141 8.5498 9.5839 10.6933 $`SNRL1 Core 230` [1] 7.6810 8.7648 9.8382
2013 Jan 22
1
How to remove the vertical space between two graps
Hi, I have created a barplot using the following code. a<-c(11,23,15,34,42,31) m<-matrix(a,nrow=2) m[2,]<-(-1)*m[2,] par(mar=c(4,4,4,0)) barplot(m[2,],horiz=T) par(mar=c(4,0,4,2)) barplot(m[1,],horiz=T,col="black") and the plot obtained is shown in "plot1.tiff". I was not willing to see the gap (vertical space) between two graphs. How can I achieve it? Further
2012 Oct 25
2
Regarding the memory allocation problem
Dear All, My main objective was to compute the distance of 100000 vectors from a set having 900 other vectors. I've a file named "seq_vec" containing 100000 records and 256 columns. While computing, the memory was not sufficient and resulted in error "cannot allocate vector of size 152.1Mb" So I've approached the problem in the following: Rather than reading the data
2012 Oct 08
1
Any better way of optimizing time for calculating distances in the mentioned scenario??
Dear All, I'm dealing with a case, where 'manhattan' distance of each of 100 vectors is calculated from 10000 other vectors. For achieving this, following 4 scenarios are tested: 1) scenario 1: > x<-read.table("query.vec") > v<-read.table("query.vec2") > d<-matrix(nrow=nrow(v),ncol=nrow(x)) > for (i in 1:nrow(v)){ + d[i,]<-