search for: chab

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2010 Nov 19
2
Ekiga can register but not my IP phone
...low=speex [siemens] type=friend context=interne host=dynamic secret=xxxxxxxx When i'm doing a sip set debug ip XXX.XXX.XXX.XXX i have some information. It seems that asterisk receives the rengistration request but doesn't answer to it. Here are the logs : http://server.chab.info/Registration_logs_ip_phone.txt Using Ekiga with the same SIP account (name is siemens) and from the same physical location works well : http://server.chab.info/Registration_logs_ekiga.txt I didn't change anything about asterisk config (except sip.conf and extensions.conf). If you have an...
2010 Oct 12
2
repeating an analysis
...ode (and relevant output) for the analysis I am running. I need to run it n=50 times and from each output pick the appropriate tree size and post it to a datafile where I can then look at the frequency distribution of tree sizes. Here is the code and output from a single run > fit1 <- rpart(CHAB~.,data=chabun, method="anova", control=rpart.control(minsplit=10, cp=0.01, xval=10)) > printcp(fit1) Regression tree: rpart(formula = CHAB ~ ., data = chabun, method = "anova", control = rpart.control(minsplit = 10, cp = 0.01, xval = 10)) Variables actually used in tree...
2011 Mar 10
10
JS data to rails view helper
I have a view helper like ryan bates complex forms task helper, rails 2.2.2. Anyway is there a way to send the value selected in a select menu to the helper? I am trying to do stuff without going back to the server. <%= select_tag :discout_code, options_for_select(@discount_codes)%><%= add_exclusion_date_link(''Add Existing'', JS ) %> -- You received this
2010 Oct 25
0
penalized regression analysis
...variance explained information from and how do I determine the relative importance of the 4 variables selected? It does not appear to be a part of the penalized procedure. I submit the final call to 'penalized' with the estimated values of lambda1 and lambda2 > fitfinal <- penalized(CHAB~.,data=chabun,lambda1=356.0856,lambda2=3.458605,model = "linear",steps=1,standardize = TRUE) # nonzero coefficients: 5 > fitfinal Penalized linear regression object 10 regression coefficients of which 5 are non-zero Loglikelihood = -154.1055 L1 penalty = 4944.889 at lamb...
2010 Oct 15
0
nomianl response model
...have your solution and another which I will attempt in the next day or so and will post results to the list then. cheers andy On Wed, Oct 13, 2010 at 10:30 AM, Phil Spector <spector at stat.berkeley.edu>wrote: > Andrew - > I think > > answer = replicate(50,{fit1 <- rpart(CHAB~.,data=chabun, method="anova", > > control=rpart.control(minsplit=10, > cp=0.01, xval=10)); > x = printcp(fit1); > x[which...