Displaying 3 results from an estimated 3 matches for "cforest_control".
2012 Jun 15
0
argument "x" is missing, with no default - Please help find argument x
...mtry, rownumber=rownumber, ntrees=ntrees,
shuffled=shuffled) {
require(party)
require(epiR)
test<-rownumber[[i]]
train<-shuffled[shuffled!=test]
cv.train <- ml.frame[train,]
cv.evaluate <- ml.frame[test,]
cv.model <- cforest(as.factor(remitter)~., data=cv.train,
control=cforest_control(mtry=mtry, ntree=ntrees, mincriterion=0.95))
cv.evaluate$prediction <- predict(cv.model, newdata=cv.evaluate)
obj.pred<-predict(cv.model)
pred.table<-table(cv.evaluate$prediction, cv.evaluate$remitter)
truepos<-pred.table[1,1]
trueneg<-pred.table[2,2]
falsepos<-pre...
2008 Sep 25
0
varimp in party (or randomForest)
...sep = " ", na.string = "X")
#arabidopsis <- subset(arabidopsis, complete.cases(arabidopsis))
arabidopsis <- subset(arabidopsis, is.na(arabidopsis$edit)==FALSE)
arabidopsis <- arabidopsis[, !(names(arabidopsis) %in% c("X0", "loc"))]
my_cforest_control <- cforest_control(teststat = "quad",
testtype = "Univ", mincriterion = 0, ntree = 50, mtry = 3,
replace = TRUE)
my_cforest <- cforest(edit ~ ., data = arabidopsis,
controls = my_cforest_control)
varimp_cforest <- varimp(my_cforest)
By t...
2012 Sep 13
0
cforest and cforest_unbiased for testing and training datasets
...ed # of samples in my testing dataset? The resulting
analysis will be applied to my specified testing dataset to assess
misclassification and accuracy. I am aware that the options of
cforest_unbiased do not allow allow the fraction value to be altered so my
second question is is data.controls <- cforest_control(teststat = "quad",
testtype = "Univ", replace = FALSE, ntree=2000, mtry=2, fraction=.99) the
equivalent to data.controls <- cforest_unbiased(ntree=2000, mtry=2) except I
have eliminated the default testing dataset?
Thank you for your help
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