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i have a data set with repeated measures on same people, structure like below: id x1 x2 ... 001 10 20 ... 001 8 45 ... 001 4 2 ... 002 .... 002 ... 002 .... 002 .... 003 .... ....... what is the easist way to show how many observations for each subject id? [[alternative HTML version deleted]]

... and is there also such a nice tool (like spss.get) for exporting data frames to SPSS? write.table does not keep the data frame labels - neither did the other exporting tools that I found. Thanks! Michael [[alternative HTML version deleted]]

I have a data set where I want the correlations between 2 variables conditional on a students grade level. This code works just fine. by(tmp[,c('mtsc07', 'DCBASmathscoreSPRING')], tmp$Grade, cor, use='complete', method='pearson') However, this generates an error by(tmp[,c('mtsc07', 'DCBASmathscoreSPRING')], tmp$Grade, cor, use='complete',

Hello, A made a xyplot using the lattice library in R (latest version). The publisher of our paper has requested: 1. all tick marks should point inwards instead of outwards. 2. All lines should be thicker (lines, axes, boxes, etc. Everything). Lines is easy...I used: lwd=1.5 but what about the lines of the axes, and the lines that build up the plot itself?....? Any

A colleague was asking me if R does multi-level modelling as opposed to multiple regression. Since I have no knowledge of multi-level modelling (except 5 minutes googling ) I thought that I would as here. Does are offer any multi-level modeling packages? It looked like arm might be one but I was not sure. Thanks

Hello: I recall something like this being discuss recently, but I can't seem to locate an example in the archives. I have data like the following: df <- expand.grid(1:4, 1992:2002) names(df) <- c("MSA", "YEAR") df$IDUPREV <- runif(44) df$VALIDAT <- rnorm(44) I want to create an xyplot() with separate loess lines for each series (IDUPREV and VALIDAT) in

Dear R Users, If it is possible, i would like to learn whether a R package that can be used for Taguchi design is available. Sincerely -- Ýbrahim Mutlay [[alternative HTML version deleted]]

What is the right way to assign a new variable into each a of list of data frames? Here is my failed attempt: mylist <- list(df1 = data.frame(A = runif(5), B = runif(5)), df2 = data.frame(A = runif(5), B= runif(5))) lapply(mylist, function(x){x$Y <- x$A * x$B}) $df1 [1] 0.25589928 0.03446026 0.94992362 0.21388326 0.08668821 $df2 [1] 0.08771839 0.05643553 0.09036894

Dear latexRs, I tried to make a latex printout of a simple categorial ftable. It should look like the output of print.ftable. Any ideas how to get the syntax of summary.formula right. Or some alternative? As far I see, xtable does not have method for ftable. Dieter library(Hmisc) n=500 sex <- factor(sample(c("m","f"), n, rep=TRUE)) treatment <-

Dear All, Need some help in polynomials transformation to get the coefficients. I have tried "poly.transform" as applied in S-plus but it does not work. Thanks in advanced for any helps. Regards. Abd. Rahman Kassim (PhD) Head Forest Ecology Branch Forest Management & Ecology Program Forestry and Conservation Division Forest Research Institute Malaysia Kepong 52109 Selangor,

Hi all, Suppose I have a column vector of 600 measurements taken in 1s intervals. What I want is a new vector with the averages for each min (so there would be 10 entries). Is there an efficient way to do this? I’ve been doing it with a ‘for’ loop but something tells me there is a simple command that is more efficient. Jeff Internal Virus Database is out-of-date. Checked by

Running R 1.8.1 on a Windows machine In dotchart, I would like to shrink the labels on the tick marks (that is, the numbers) without shrinking anything else. I could not find this in either the Rhelp archives or in ?dotchart, which recmmends cex to avoid 'label overlap', but cex shrinks all the characters in the plot. Is there a way to do this? Thanks Peter Peter L. Flom, PhD

Hello! I?m fitting a model with glm(family binomial). The best model counts 9 Variables and includes an interaction term that was generated by the product of to continuous variables (a*b). All variables are correlated under a value of 0.7 (Spearman rank order) While the estimates of both main effects are negativ, the resulting interaction term is positiv. This change of sign makes it difficult to

Hi, Given a vector, say x=sample(0:9,10) x [1] 0 6 3 5 1 9 7 4 8 2 I can find the location of an element by which(x==2) [1] 10 but what if I want to find the location of more than one number? I could do c(which(x==2),which(x==3)) but isn't there something more streamlined? My first guess was y=c(2,3) which(x==y) integer(0) which doesn't work. I haven't found any clue in the R

Dear R-helpers, I have a problem which I suppose is trivila, but... I have included NA values as factors ( (to be able to make nice printed summaries with NAs % ba category ) with the following code dat$x.f<-factor(dat$x, exclude=NULL); levels(dat$x.f)<-c("A1","A2","A3","A4","NA"); length(dat$x.f) Now, I want to impute the missing values.

I have data in the following form: ID COUPON0 COUPON1 COUPON2 COUPON3 1 1 1000 1001 1002 2 2 NA NA NA 3 1000 1003 NA 1004 4 1001 NA 1005 NA 5 1002 NA NA NA 12 1003 NA NA 1006 7 1005 NA NA NA 8 1004 1007 NA NA 9 1006 NA NA NA 26

Hi R, I have a vector V1 of unknown length, say n. I need to convert this into a matrix C of row size=5, and accordingly the column should be updated. I tried with: C=as.matrix(V1,5,n/5) But it is not working...Could somebody help me on this? Thanks in advance... [[alternative HTML version deleted]]

Hello I have a dataset in which I would like to replace 0s with NAs. There is a lot of information on how to replace NAs with 0, but I have struggled to find anything with regards to doing the reverse. Any recommendations would be great. Cheers Christine

Dear all, I am trying to learn R. Is it possible to find the mean of some rows (of some table) and to put it in new table. For example we have following table date x y z 1 05-23-2001 7 1 3 2 05-24-2001 8 4 5 3 05-24-2001 6 0 0 4 05-24-2001 26 2 6 5 06-19-2001 0 7 0 6 06-19-2001 5 0

Hello, I'm new to R, I've been working with it for the last 2 weeks. I am plotting some data and not getting the labels on the x axis I am expecting on my plot. my code reads #hours in the day h <- c(0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23) #hp is a data frame with a pivot table of 25 columns (label and data for 24 hours) plot(h, as.matrix(hp[1,2:25]),