Displaying 1 result from an estimated 1 matches for "caseall".
Did you mean:
casale
2012 Mar 01
2
'break' function in loop
...probably I put the break function under the wrong loop but I cannot fix it. Sorry if the whole script looks quite messy, I will be very appreciate if someone can help me fix this problem or probably give me some advices to write it in a smart way.
My attempt:
controlall <- rbeta(10000,1.5,6)
caseall <- rbeta(10000,1.6,6)
results <- NULL
results1 <- NULL
or <-vector("list",length=10)
criteria <- matrix(data=c(1.05,1.15,1.15,1.25),ncol=2,nrow=2)
for (k in 1:2) {
for (i in 1:1000)
{
control <- sample(controlall,100)
case <- sample(caseall,1...