search for: carole

Hello, It might be an easy question but if you have many variables to fit in the lm function, how do you take all without specifying var1+var2+...+var2100 in the terms parameter in response ~ terms? Cheers, Carol

It seems that there is a problem in displaying subtitle in general, independently from multi-plot display. when I do plot (c(1,2,3), c(9,8,7), type = "l") title(main = "Main title", sub ="Sub title",cex.main=2, cex.sub = 2) subtitle doesn't get displayed > --- On Sat, 11/21/09, David Winsemius <dwinsemius at comcast.net> > wrote: >

Hi, What is the function for inverse normal transformation? Thanks, Carol [[alternative HTML version deleted]]

Hi, I got problem in using title function to create a title for multiple plots presented together by par. As can be seen in the attached file, the title is displayed truncated and the subtitle doesn't get displayed. Here is the code: par(mfrow = c(1,2)) plot(c(1,2,3), c(9,8,7)) plot(c(1,2,3), c(9,8,7)) title(main = "Main title", sub ="Sub title",outer = TRUE,

I'm trying to use samba to serve a number of home directories to other samba Linux clients on my network. ie. I have a set of client machines that want to use the /home directory that my samba server will provide I thought I could set up a share that goes something like this [homedirs] path = /home writable = true On a client machine, I smbmount //myserver/homedirs

Hi, In this thread http://lists.digium.com/pipermail/asterisk-users/2008-October/219592.html , I wondered whether SIPPEER curcalls was working. I could test this anew today. Here are my findings : Alice, Bob and Carol ar all using SIP Phones. Whenever Alice is calling Bob, - if Carol is calling Alice, SIPPEER(Alice:curcalls) equals 0 - if Carol is calling Bob, SIPPEER(Bob:curcalls) equals 1

Hi, Does anyone know how to take a time difference when the format of the time is as 13:22:23.586? I am trying to take the difference of time between stock transactions and need to keep the three decimal places for seconds. I have tried *diff(strptime(x, "%H:%M:%S.000))*, but apperantly that doesn't work. Carol Gao [[alternative HTML version deleted]]

Hi, How to plot the same types of graphics on the same R graphic device? Suppose that we want to plot a vector y against x (using plot for instance). How is it possible to plot y against x for different values of these two vectors on the same device so that the plots could be compared? Cheers, Carol [[alternative HTML version deleted]]

Hi, We could use qqplot to see how two distributions are different from each other. To show better how they are different (departs from the straight line), how is it possible to plot the straight line that goes through them? I am looking for some thing like qqline for qqnorm. I thought of abline but how to determine the slope and intercept? Best wishes, Carol

Hello, How is it possible to sort dates in R? Cheers, Carol

Hi, I wanted to plot the histogram of a vector and then, plot the density function of subsets of the vector on the histogram. So I use truehist in MASS package and lines(density) as follows: length(b) = 1000 truehist(b) lines(density(b[1:100])) however the density plot of the first 100 points exceeds the max of y axis (see attached). how is it possible to make a graphics so that the density plot

Have UI that simplifies running code from another (internal) package, allowing user to set values on fields I basically grabbed from results of calls to formals() for various functions. That works fine for the most part. But it was requested to investigate some type of popup help or something for each field. Since I already wrote the information in the dot-Rd files for what should be displayed,

Thanks, bjornr, however your suggestion to try: wine "C:\Program Files\intuit\qbtimer\qbtimer.exe" gave the same result as the other command lines I tried. All invoke the qbtimer program and all get the same error from qbtimer: Can't find timer file "Files/intuit/qbtimer.exe" ... So wine properly finds the qbtimer.exe file. The error arises after the program is

Hi. Assume you have an array of person names. I want to generate results in my view that look like this: Abby is your friend or Abby, Bob, and Carol are your friends. So I''d like to say: <%= friends.to_sentence %> <%= pluralize(friends.count, "is") %> your <%= pluralize(friends.count, "friend") %> But because pluralize puts in the

Hi, Having a set of values (non-time series data), what are the approximation functions that could determine the trend of the values? Cheers, Carol [[alternative HTML version deleted]]

Hi, It might be a primitive question but how it is possible to determine if a variable is initialized in an environment? Suppose that we start a R session and wants to run a script which use the variable i. Which function could evaluate if i is already initialized or not and if not, then ask interactively the user to set it? This is to avoid the error message: object i is not found. Regards,

2008/11/4 Igor Zamocky <asterix at ponozky.sk> > > Did You tried http://www.voip-info.org/wiki/view/Asterisk+sip+limitonpeers > ? > I didn't. Now I did and it's working the way I wanted. Meanwhile, I had found a (complex) workaround using GROUP, GROUP_COUNT and SIPPEER but limitonpeers is much more concise. Thanks a lot. > > > Hi, > > > In this

hi list, environment: Windows 2008 Domain Centos 7 server running samba 4.4.4 Problem: I am creating a number of samba shares on the Centos server to be used on the Domain. Right now I have two major directories setup as shares with minor directories being created. How do I specify read/write permissions on the minor directories without having to create a share for each directory?  When I

Hi, How is it possible to extract athe elements of a list of vectors in a fixed position? suppose that I have a list of 2-element vectors, how can I extract the 2nd element of all vectors in the list? Can it be done with indexing and not by element name? Thanks carol So in this example, I want to extract 2 and 4 v = list (c(1,2), c(3, 4)) > v [[1]] [1] 1 2 [[2]] [1] 3 4

Hi Every one, I have a dataframe "class" with "name", "sex", "age", "height", "Weight". if i caluclate summary statistics with the below code numSummary(class[,c("Height", "Weight")], groups=class$Name, statistics=c("mean", "sd", "quantiles"), quantiles=c(0, .25,.5,.75,1)) iam getting