search for: bw1

...8,0.24,0.41,0.97, 0.82,0.11,0.53,0.80,0.71,0.31,0.70,0.00,0.90,0.88,0.15,0.49,0.54,0.89,0.07,0.09,0.34, 0.20,0.73,0.37,0.94,0.49,0.40,0.55,0.68,0.89,0.00,0.42,0.94,0.06,0.53,0.46,0.11,0.96, 0.41,0.69) I need to find out the bandwidth and I have two ways of doing it as # as per the stats package bw1 = bw.nrd0(recovery_rates)             #    which gives me bw1 = 0.1050780 # as per the KernSmooth package bw2 = dpik(recovery_rates)                    #    which gives bw2 = 0.1027932 I am bit confused which bandwidth is to be used. Is it that "statistics package" deal with univariate...

...printer = col2-pet printable = yes writeable = yes browseable = yes force user = root force group = root [bw2-box] # # print ok=yes path = /var/spool/samba printer = bw2-box printable = yes writeable = yes browseable = yes force user = root force group = root # hosts allow = 10.3.101. 127. [bw1-pet] print ok=yes path = /var/spool/samba printer = bw1-pet printable = yes writeable = yes browseable = yes force user = root force group = root [col1-7floor] # # print ok=yes path = /var/spool/samba printer = col1-7floor printable = yes writeable = yes browseable = yes force user = root force g...

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