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2009 Oct 19
2
Using grep to determine value of last letter...
...lue of the last character and then take the appropriate action, e.g.
If the value is L then label UL rating XXX
It the value is F then label UL rating YYY
...
I assume it will be something like the following:
grep("last letter", HousesWithCodes$Codes)
Thanks again for any insights.
BuildYear<-c(1980, 1985, 1975, 1990, 1980)
SqrFootage<-c(1500, 1650, 1500, 2000, 1450)
Exterior<-c("Brick", "Stone", "Siding", "Brick", "Siding")
SubdivisionHouses<-data.frame(BuildYear, SqrFootage, Exterior)
Year<-c(1980, 1985, 1975, 1990, 1...