search for: brecknock

...09.xls", : cannot open URL 'http://ir.eia.gov/wpsr/psw09.xls' In addition: Warning message: In download.file("http://ir.eia.gov/wpsr/psw09.xls", "c:\\temp\\psw09.xls", : InternetOpenUrl failed: 'The operation timed out' Thanks for any insights. Pete Brecknock -- View this message in context: http://r.789695.n4.nabble.com/Problems-downloading-file-tp4435186p4435186.html Sent from the R help mailing list archive at Nabble.com.

I have a zoo object that contains 2 time series named "A-B" and "V1". When I create a third series "V2", the name of the "A-B" series is changed to "A.B". Although I could recreate the names for the 3 series I am wondering if there is a way of preventing the name change from happening ( ... maybe an equivalent of the keep.names=TRUE statement

Hi All Apologies if this is not the correct list for this question. The Rglpk package offers the following example in its documentation library(Rglpk) ## Simple mixed integer linear program. ## maximize: 3 x_1 + 1 x_2 + 3 x_3 ## subject to: -1 x_1 + 2 x_2 + x_3 <= 4 ## 4 x_2 - 3 x_3 <= 2 ## x_1 - 3 x_2 + 2 x_3 <= 3 ## x_1, x_3 are non-negative integers ## x_2 is a non-negative real

I am trying to rename column names in a dataframe within a function. I am seeing an error (listed below) that I don't understand. Would be grateful of an explanation of what I am doing wrong and how I should rewrite the function to allow me to be able to rename my variables. Thanks. # Test Function myfunc <-function(var){ d = c(1,2,3,4,5) dts =

kiotoqq wrote > I want to add a shorter column to my dataset with the function "merge", > it > should be filled with NAs wo be as long as the other colums, like this: > > id age > 9 46 > 8 56 > 6 52 > 5 NA > 4 NA > 3 NA > 1 NA > > i did this: > pa1 <- merge(pa1, an1, by="mergeid") > > and it says

Hi All I am running a linear regression using the lm object. In the event that my independent variable is the same across all observations the regression slope is returned as an NA. For example, if I have the following y=c(10,12,17) x=c(5,5,5) lm = lm(y~x) produces the following Coefficients: (Intercept) x 13 NA Other than post-processing the results, is

Hi All I am trying to use the round function on some columns of a dataframe while leaving others unchanged. I wish to specify those columns to leave unchanged. My attempt is below - here, I would like the column d3 to be left but columns d1, d2 and d4 to be rounded to 0 decimal places. I would welcome any suggestions for a nicer way of doing this. d1= rnorm(10,10) d2= rnorm(10,6) d3=

fitz_ra wrote > I know this is posted a lot, I've been through about 40 messages reading > how to do this so let me apologize in advance because I can't get this > operation to work unlike the many examples shown. > > I have a 2 row matrix >> temp > [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] > [,9] [,10] > [1,] 17.000

Hi All I have a vector x containing 2 levels x = c(1,1,1,0,0,0,0,1,1,0,0,0,1,1,0) I would like to derive the following summarization Level Count 1 3 0 4 1 2 0 3 1 2 0 1 I have generated an inelegant solution using lags and loops but feel sure that there must be a better approach. If anyone has any thoughts I would be very grateful if you would share them. Thanks and best regards Pete --

simonj16 wrote > Consider an urn that contains 10 tickets, labelled: 1,1,1,1,2,5,5,10,10,10 > > I want to draw with replacement n=40 tickets. I am interested in the sum, > Y, of the 40 ticket values that I draw > > Write an R function named urn.model that simulates this experiement. What > I have below is not working. > > flip.n = function(p,n) { >

Hi I would like to understand how to extend the function (FUN) I am using in rollapply below. ###################################### With the following simplified data, test1 yields parameters for a rolling regression data = data.frame(Xvar=c(70.67,70.54,69.87,69.51,70.69,72.66,72.65,73.36), Yvar =c(78.01,77.07,77.35,76.72,77.49,78.70,77.78,79.58)) data.z = zoo(d) test1 =

cdouglass wrote > Hello all, > > Totally new to this and I'm just doing a frequency distribution analysis > on T-shirt sales by size. I have a .csv with 60 orders. I read in the > data using read.csv. If I look at the summary() or table() of the data it > looks fine, except that the shirt sizes are alphabetical rather than from > S-XXL--so the bar graph loses the shape

I am positive this problem has a very simple solution, but I have been unable to find it, so I am asking for your help. I need to know how to look something up in one data frame and add it as a column in another. If I have a data frame that looks like this: > frame1 ID score test age 1 Guy1 10 1 20 2 Guy1 13 2 20 3 Guy2 9 1 33 4 Guy2 11 2 33 and another frame that looks like this:

Hi, I want to generate 10000 samples from normal distribution with replacement case and every sample size is 50. What should I do ? -- View this message in context: http://r.789695.n4.nabble.com/IMPORTANT-PLEASE-HELP-ME-tp4650676.html Sent from the R help mailing list archive at Nabble.com.

Hi its me again I don't mean to get on your nerves, but the use of R proofs to be a bit more complicated than envisaged. I would like to calculate the mean of a group of values, here "wage_accepted". The group is determined by the stage and period, so in the end there should be a column with the values of the wages in period 1 stage1, period 1 stage 2, period 2 stage1...

I am trying to create a frequency distribution and I am a bit confused. Here are the commands I have entered: > data <- read.csv(file="40609_sortedfinal.csv",head=TRUE,sep=",") > NumberOfActionsByStatus = data$STATUS > NumberOfActionsByUser = data$ETS_LOGIN > NumberOfBidOffer = data$BID_OFFER > NumberOfActionsByUser.freq = table(NumberOfActionsByUser) >

...Wiley) > 49. Re: a remove question (David Winsemius) > 50. Re: a remove question (Hugo Mildenberger) > 51. Computing and Finding (ufuk beyaztas) > 52. WORK AREA TO SAVE (Barbara.Rogo@uniroma1.it) > 53. Re: WORK AREA TO SAVE (Duncan Murdoch) > 54. Re: a remove question (Pete Brecknock) > 55. Re: Memory issues (Chris Howden) > 56. Re: how to calculate the consistency of different clusterings > (Michael Bedward) > 57. Re: ODD ODD ODD stuff!! (Sarah Goslee) > 58. Re: rootogram for normal distributions (Deepayan Sarkar) > 59. effects packages for mixed mo...

Hi All Apologies if this is not the correct mailing list for this question. I have installed RExcel and RCom from CRAN. R is indicating that I need an additional file/package "statconnDCOM" from rcom.univie.ac.at I have been trying to access this website over the last 2 days be it appears to be down. Does anyone know when this site is likely to be back up and/or know of an

David Stoffer describes some challenges with R's output when fitting ARIMA models for different orders (see Issue 2 at http://www.stat.pitt.edu/stoffer/tsa2/Rissues.htm). R doesn't fit an intercept in the model if there is any differencing. David describes a workaround using the xreg parameter to force R to calculate an intercept. Assume I have a variable y and 3 explanatory variables a,

Amy It would have been helpful if you had sent your R code of how you constructed the sab object. If you have a data.frame, the subset command you are having trouble with should work fine. See below. # Working Example sab = data.frame(group=c('Group A', 'Group A', 'Group C', 'Group B', 'Group C'), gender=c(1,1,1,2,2)) subset(sab, sab$group=='Group