Displaying 1 result from an estimated 1 matches for "breakdown2".
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breakdown
2006 Apr 20
0
Breakdown a number [Broadcast]
...han my description.
>
>
> > > bp <- c(0, 250, 800, 1200)
> > > diff(bp)
> > [1] 250 550 400
>
> Don't think diff method is going to work either, at
> least in cases where the 'whole' is less than greatest
> 'break'.
>
> > breakdown2 <- function(x, breaks = c(250, 800)) {
> diff(c(0, breaks, x))
> }
> > breakdown(10) # 10 0 0
> > breakdown2(10) # 250 550 -790
> >
> > breakdown(400) # 250 150 0
> > breakdown2(400) # 250 550 -400
>
>
> ------------------------------------...