search for: botelho

...omatically detects that 5.4 is available and move update for it when i run yum update. How does this work? How the system detects new version and update for it? I thought centos-release rpm just update repo for it, but I saw this is not the case. Could someone gimme some light? Thanks -- Renato Botelho

Hello everyone! How can I detect if a folder have changed (sync logic) than run a script if it's true? I found this script over the net, but I think it's such complicated for that simple thing... #!/bin/bash ############### detectdir.sh by Jagbir Singh ################# # # script to detect changes in directory. #

...regressions changing the dependent variables for the same period. I believe your solution might be similar to that one, just making the window dynamic instead. I used a lapply to store regressions and sapplys to extract stats from the lm()s. Please check the attachment and hope it?s useful. Filipe Botelho -----Mensagem original----- De: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] Em nome de Caio Ramos Casimiro Enviada em: ter?a-feira, 31 de maio de 2011 12:23 Para: r-help at r-project.org Assunto: [R] Using lm() combined with sapply Dear list, I spent a lot of time lo...

...rver (e.g. ftp.FreeBSD.org), data connection doesn't work. Connection comes to my firewall and is accepted but connection is not established and stay like this here: self tcp 200.x.x.x:57625 <- 200.x.x.x:20 ESTABLISHED:FIN_WAIT_2 Any kind of help will be appreciate thanks -- Renato Botelho

Dear all, I have a matrix X which consists of 2 columns. I would like to convert this matrix into a list where every entry of the list consists of a single row of the matrix. Does anyone have a suggestions how to manage this? Thank you for your efforts in advance! Best, Martin [[alternative HTML version deleted]]

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hello, I have a simple question on the text() method in plots, e.g.: text(3,4,adj=1,cex=1.0, expression(alpha == beta)) I know there exists a lot more like frac(), etc which could be used for expression. But a help(frac) doesn't return any results - where do I have to look for a documentation of possible text commands? More in detail I'm

I noted centos-release source rpm is missing on repositories, and after search a bit I found this thread: http://www.linux-archive.org/centos/272321-centos-release-srpm.html Anyone have news about this? Thanks in advance -- Renato Botelho

Hi friends, I have got a list where each element might have variable number of members. $`4213` [1] "214077_x_at" $`164832` [1] "225996_at" "235977_at" $`339010` [1] NA $`23410` [1] "221562_s_at" "221913_at" "49327_at" $`285386` [1] "229764_at" $`2099` [1] "205225_at" "211233_x_at"

Hello R-help   I am trying to copy and paste large column of data from windows Excel into R base speed sheet using:   Data1<-edit(data.frame())   But I can only copy and paste one cell at a time which is time consuming.   Also how can assign each column to a variable. [[alternative HTML version deleted]]

Hi all, I need to run several simple linear regressions at once, using the following data. Response variables: Bird species (sp 1, sp2, sp3...spn). Independent variable: Natprop - proportion of natural area. covarate: Effort = hours). One single linear regression would be: lmSp1 <- lm(sp1~ natprop + effort). However, I need to run this linear regression for all bird species that I have

Hi, I've a data frame like this: > as.data.frame(cbind(rnorm(1:12),rnorm(1:12))) V1 V2 1 -1.30849402 -0.52094136 2 0.96157302 0.76217871 3 -0.44223351 -1.72630871 4 -0.10432438 -1.04732942 5 -1.38748914 0.95877311 6 -0.63965975 0.65494811 7 -0.24058318 0.19496830 8 -0.11172988 1.01680655 9 0.08065333 0.22168589 10 0.25196536 0.84619914 11

Hey R-Comunity, I'd like to print out an histogram of some experimental data and add a smooth curve of a normal distribution with an ideally generated population having the same mean and standard deviation like the experimental data. The experimental data is set as vector x and its name is set to group.name. I paint the histogram as follows: hist(data, freq=FALSE,

Dear all, i am doing linear regression with robust error to know the effect of a (x) variable on (y)other if i execute the command i found positive trend. But if i check the effect of number of (x.x1,x2,x3)variables on same (y)variable then the positive effect shwon by x variable turns to negative. so plz help me in this situation. Barjesh Kochar Research scholar

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 R Help Mailing List, I'd like to generate a plot that I could display and/or store it as e.g. jpeg. But unfortunately always a plotting window opens. Is it possible to prevent that? I tried the following: R> bp<-boxplot( sample(100), plot=FALSE) This works somehow, but it only stores data (as discribed in the help) in bp and it is not

...*/ PSFS_FEED_ME, /* filter needs more data; stop processing chain until more is available */ PSFS_PASS_ON, /* filter generated output buckets; pass them on to next in chain */ } php_stream_filter_status_t; Removing comma after PSFS_PASS_ON everything back to normal. -- Renato Botelho

Hi, I have two datasets, x and y. Simplified x and y denote: X Y A B C A B C . . . . . . . . . . . . . . . . . . I want to implement all possible models such as lm(X$A~Y$A), lm(X$B~Y$B), lm(X$C~Y$C)... I have tried the following: fun<- function(x,y){ for(i in 1:length(colnames(x))){ for(j in 1:length(colnames(y))){

Hi everyone Please, I need one more help you I have some data that need to make a forecast. I´m using the command: Yst<-print(ts<-ts(Y,start=c(1,5),freq=7),calendar=T) to create the dayly time series by the dataframe Y. My data Y means: Y=measure dayly , start at 01/jul/2010 (thursday), for this reason that I use c(1,5). I need to create the time series aggregate by weakly (and not dayly as

Dear R mailing-list comunity! I'm currently trying to implement an R method. I have two sets of data that I convert into a data.frame each. These data.frames I'd like to append to a list: # generate a list listTable<-list() # add one set of data x<-1000 ;y<-1 ;listTable[[length(listTable) + 1]] <- data.frame(matrix(rnorm(x*y), nrow=y)); rm(x); rm(y) # add another set of

...or any help.. Sirius -- View this message in context: http://r.789695.n4.nabble.com/optimization-in-for-loop-tp3633638p3633638.html Sent from the R help mailing list archive at Nabble.com. ------------------------------ Message: 46 Date: Wed, 29 Jun 2011 15:37:24 -0300 From: "Filipe Leme Botelho" <filipe.botelho at vpar.com.br> To: "tomtomme" <langkamp at tomblog.de>, <r-help at r-project.org> Subject: [R] RES: time series interpolation Message-ID: <07E17EE73DE13B4897BC6FE325CF7A2401834953 at BRSAOWSEXCL001.votorantim.grupo> Content-Type: text/pla...