Displaying 5 results from an estimated 5 matches for "boshao".
2010 Oct 28
3
get the rows so that there is no redundant element in a certain column
...f this column are redundant. Or sometimes, to have a look at the rows that the elements of this column are redundant is also important. I guess it boils down to throw out the index of the redundant elements.
With millions of rows, how can I efficiently perform the task?
Thank you in advance.
Boshao
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2008 Mar 19
1
weibull model
...to fit a Weibull model using R, you
are my savior for my project. The hazard ramda is
specified as t^alpha * (1+a*dose*exp(-b*dose)).
Or, can we modify the Cox model to capture the
proportional part above? Here t is the survial time,
dose is a subject received in a exposed group.
Thank you a lot.
Boshao
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2004 Jul 13
1
MLE, precision
...ues of
grid point. It works well. Also, you can get the
correct answer of log(1e-12).
My questions are:
What is the precision of a variable in R?
How to specify the constraint interval of parameters
in nlm? I tried lower, upper, it doesn't work.
any advice on MLE is appreciated.
Thank you.
Boshao
2010 Jan 11
2
help needed to find zero areas in a vector
Dear Helpers:
I spend more than half a day to solve this problem in R:
Let x be a vector of a string of 0s and 1s, such as
x<-c(0,0,1,1,0,0,0,0,1,1,0,0,0,0). It can be a very long vector.
How to sub vectors of 0s? In the above example, I would like get the vectors (0,0), (0,0,0,0), (0,0,0,0).
I can use which(x==0) to get the index of the 0 elements, but I don't know how to get the
2007 Nov 26
1
pass lm( ) a char vector as the variables to be included
...va(lm.D9 <- lm(weight ~ group))
lm.D90 <- lm(weight ~ group - 1) # omitting intercept
What I am doing is let the variable name "group"
stored in a vector, say, g <- "group". The question is
how to strip the quotation marks when we call lm( )
through g?
Thank you all.
Boshao
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