Displaying 1 result from an estimated 1 matches for "bn1994".
Did you mean:
bn1993
2008 May 06
2
list manipulation
...each output as demonstrated below. How can I generate this
(and similar) result(s) without all the trailing NULLs?
> lapply(ls(pattern='bn'), function(x) cat(x, dim(get(x)), "\t",
names(get(x)), "\n"))
bn1993 2885 11 oplt rplt rsiz tree bd ht oaz odst raz rdst spr
bn1994 3158 7 oplt tree bd ht spr stat dam
bn1995 734 7 oplt tree bd ht spr stat dam
bn1996 293 7 oplt tree bd ht spr stat dam
bn1997 264 7 oplt tree bd ht spr stat dam
bn1998 768 7 oplt tree bd ht spr stat dam
bn1999 654 7 oplt tree bd ht dbh stat dam
bn2003 1407 9 oplt tr...