Displaying 3 results from an estimated 3 matches for "block6".
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block
2002 Sep 11
0
Contrasts with interactions
...ment10 0.43933 0.53421 0.822 0.411823
block2 -1.87242 0.66448 -2.818 0.005312 **
block3 0.10927 0.22670 0.482 0.630328
block4 -1.45648 3.71684 -0.392 0.695574
block5 0.25447 0.22033 1.155 0.249475
block6 -0.32177 0.22269 -1.445 0.150021
treatment1:block2 -0.38808 0.26398 -1.470 0.143073
treatment2:block2 -16.54735 6.85505 -2.414 0.016671 *
treatment3:block2 2.58861 0.75571 3.425 0.000743 ***
treatment4:block2 1.00025 0.71152 1.406 0.161319
t...
2002 Aug 06
2
AOV in MASS not the same??
...1 0.48 0.48 0.0312
0.862752
Residuals 12 185.29 15.44
---
Signif. codes: 0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1
> coefficients(npk.aov)
(Intercept) block2 block3 block4 block5 block6
51.8250000 3.4250000 6.7500000 -3.9000000 -3.5000000 2.3250000
N1 P1 K1 N1:P1 N1:K1 P1:K1
9.8500000 0.4166667 -1.9166667 -3.7666667 -4.7000000 0.5666667
The output for the ANOVA table is exactly the same as in Venables and
Ripley MAS...
2010 Apr 21
1
How to obtain the coefficients from a summary of aov ?
Dear Madame, Dear Sir,
I am able to obtain the coefficients from a 'summary' of 'lm', but NOT from a 'summary' of 'aov'.
The following example shows my steps.
## Initialize
rm(list = ls()) # remove (almost) everything in the working environment
utils::data(npk, package="MASS") # get data
model <- yield ~ block + N*P*K
## Using lm
npk.lm <-