Displaying 3 results from an estimated 3 matches for "blocb".
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2024 Jun 13
2
Create a numeric series in an efficient way
Dear Contributors
I am trying to create a numeric series with repeated numbers, not difficult
task, but I do not seem to find an efficient way.
This is my solution
blocB <- c(rep(x = 1, times = 84), rep(x = 2, times = 84), rep(x = 3, times
= 84), rep(x = 4, times = 84), rep(x = 5, times = 84), rep(x = 6, times =
84), rep(x = 7, times = 84), rep(x = 8, times = 84), rep(x = 9, times =
84), rep(x = 10, times = 84), rep(x = 11, times = 84), rep(x = 12, times =
84),...
2024 Jun 13
1
Create a numeric series in an efficient way
...13 giu 2024 alle ore 16:42 Francesca PANCOTTO <
francesca.pancotto at unimore.it> ha scritto:
> Dear Contributors
> I am trying to create a numeric series with repeated numbers, not
> difficult task, but I do not seem to find an efficient way.
>
> This is my solution
>
> blocB <- c(rep(x = 1, times = 84), rep(x = 2, times = 84), rep(x = 3,
> times = 84), rep(x = 4, times = 84), rep(x = 5, times = 84), rep(x = 6,
> times = 84), rep(x = 7, times = 84), rep(x = 8, times = 84), rep(x = 9,
> times = 84), rep(x = 10, times = 84), rep(x = 11, times = 84), rep(x = 12...
2024 Jun 13
1
Create a numeric series in an efficient way
...13 giu 2024 alle ore 16:42 Francesca PANCOTTO < francesca.pancotto at unimore.it> ha scritto:
> Dear Contributors
> I am trying to create a numeric series with repeated numbers, not
> difficult task, but I do not seem to find an efficient way.
>
> This is my solution
>
> blocB <- c(rep(x = 1, times = 84), rep(x = 2, times = 84), rep(x = 3,
> times = 84), rep(x = 4, times = 84), rep(x = 5, times = 84), rep(x =
> 6, times = 84), rep(x = 7, times = 84), rep(x = 8, times = 84), rep(x
> = 9, times = 84), rep(x = 10, times = 84), rep(x = 11, times = 84),
> rep(x...