Displaying 13 results from an estimated 13 matches for "birgitl".
Did you mean:
birgit
2008 Jun 18
2
randomForest outlier
I try to use ?randomForest to find variables that are the most important to
divide my dataset (continuous, categorical variables) in two given groups.
But when I plot the outliers:
plot(outlier(FemMalSex_NAavoid88.rf33, cls=FemMalSex_NAavoid88$Sex),
type="h",col=c("red","green")[as.numeric(FemMalSex_NAavoid88$Sex)])
it seems to me that all my values appear as
2008 Aug 06
1
Correlation dichotomous factor, continous (numerical) and ordered factor
Hello R-User!
I appologise in advance if this should also go into statistics but I am
presently puzzled.
I have a data.frame (about 300 rows and about 80 variables) and my variables
are dichotomous factors, continuous (numerical) and ordered factors.
I would like to calculate the linear correlation between every pair of my
variables, because I would like to perform a logistic regression (glm())
2008 Aug 13
2
Tiny help for tiny function
I just started to write tiny functions and therefore I appologise in advance
if I am asking stupid question.
I wrote a tiny function to give me back from the original matrix, a matrix
showing only the values smaller -0.8 and bigger 0.8.
y<-c(0.1,0.2,0.3,-0.8,-0.4,0.9)
x<-c(0.5,0.3,0.9,-0.9,-0.7,0.3)
XY<-rbind(x,y)
extract.values<-function (x)
{
if(x>=0.8|x<=-0.8)x
2008 Sep 02
2
cluster a distance(analogue)-object using agnes(cluster)
I try to perform a clustering using an existing dissimilarity matrix that I
calculated using distance (analogue)
I tried two different things. One of them worked and one not and I don`t
understand why.
Here the code:
not working example
library(cluster)
library(analogue)
iris2<-as.data.frame(iris)
str(iris2)
'data.frame': 150 obs. of 5 variables:
$ Sepal.Length: num 5.1 4.9 4.7
2008 Jun 30
1
ctree (party) plot meaning question
I tried to use ctree but am not sure about the meaning of the plot.
My.data.ct<-ctree(Resp~., data=My.data)
plot(My.data.ct)
My data.frame contains 88 explanatory variables (continous,ordered/unordered
multistate,count data) and one response with two groups.
In the plot are only two variables shown (2 internal nodes) and 3 final
nodes. Does it mean that only these two variables show a
2008 Aug 07
2
Problems using hetcor (polycor)
Sorry if this post should be long but I tried to give you a piece of my data
to reproduce my error message using hetcor:
Fehler in result$rho : $ operator is invalid for atomic vectors
Zus?tzlich: Warning messages:
1: In polychor(x, y, ML = ML, std.err = std.err) :
1 row with zero marginal removed
2: In polychor(x, y, ML = ML, std.err = std.err) :
the table has fewer than 2 rows
Error in
2008 Jul 30
2
problem with read.table()
Hello R-User
I have a table as tab-delimited textfile (291 rows, 83 columns).
The first row are labels and the first line the variable names.
I used the following code several times with different similar tables and it
always worked.
But now:
setClass("of")
setAs("character", "of", function(from) as.ordered(from))
Classe82<-cclasses <-
2008 Jun 05
2
bartlett.test()
i'm trying to test the homogeneity of variance of 92 samples each one
contains 3 observations.
to use bartlett.test function i have created a (3,92) matrix (named xx):
>bartlett.test(xx)
this message appears:
>Erreur dans bartlett.test.default(xx) :
l'argument "g" est manquant, avec aucune valeur par d?faut
when i checked the help i have understood that in g i should
2008 Aug 13
2
mob(party) formula question
I try tu use mob() with my data.frame ('data.frame': 288 obs. of 81
variables; factors, numerics and ordered factors)
My response is a binary variable and I should use for modelling a logistic
regression (family=binomial).
I read in the "MOB" Vignette that I could use a formula like this if I would
like to have only partitioning variables apart from the response.
2008 Aug 07
4
Switch two rows in a matrix
Hi all,
I have a 4 by 4 matrix, and I want to switch row 2 and row 3 first, then switch column 2 and column 3. Is there an easy way to do it?
The following is a tedious way to get what I want. But I wonder if there is a way to simplify this.
> a=matrix(rnorm(16),4,4)
> a
[,1] [,2] [,3] [,4]
[1,] 0.33833811 -0.9422273 -0.06181611 -1.8346134
[2,] -0.68167996
2008 Jul 09
0
problems using mice()
R 2.7.2
PPC Mac OS X 10.4.11
library mice 1.13.1
I try to use mice for multivariate data imputation.
My variables are numeric, factors, count data, ordered factors.
First I created a vector for the methods to use with each variable
ImpMethMice<-c(rep("logreg", 62), rep("polyreg",1), rep("norm",12),
rep("polyreg",12))
next step was
2008 Jul 10
0
ace error because of missings?
Hello RUser!
I try to use ace for an ancestral state reconstruction but got back an error
message.
ace(FacVar,Tree, type="discrete")
Warning messages:
1: In nlm(function(p) dev(p), p = rep(ip, length.out = np), hessian = TRUE)
:
NA/Inf durch gr??te positive Zahl ersetzt (NA/Inf replaced by positive
number)
2: In nlm(function(p) dev(p), p = rep(ip, length.out = np), hessian
2008 Jul 31
0
Sperman Correlation with rcorr (Hmisc)
Hello R-User!
I have a data.frame with 82 variables (columns) and 290 rows.
The variables are set to classes factor, ordered factor and numeric.
I used the following code
Matrix.My.data<-as.matrix(Df.My.Data[2:82])
Matrix.My.data.rcorr<-rcorr(Matrix.My.data, type="spearman")
and got the following message:
Fehler in storage.mode(x) <- if (.R.) "double" else