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...rval=c(0,25))    ytm = solution$root   However, when I execute this code I get following error.   > solution = uniroot(f.ytm, interval=c(0,25))  Error in uniroot(f.ytm, interval = c(0, 25)) : f.lower = f(lower) is NA Please guide. ytm should be 0.09601 (i.e. 9.601%)     with regards   Madhavi Bhave     Your Mail works best with the New Yahoo Optimized IE8. Get it NOW! http://downloads.yahoo.com/in/internetexplorer/ [[alternative HTML version deleted]]

Dear R helpers   I am calculating the 'Yield to Maturity' for the Bond with following characteristics.   Its a $1000 face value, 3 year bond with 10% annual coupon and is priced at 101. The yield to maturity can be calculated after solving the equation -   1010 = [100 / (1+ytm)]  + [100 / (1+ytm)^2] + [ 1100 / (1 + ytm)^3]   This can be solved by trial and error method s.t. ytm = 9.601%.

Dear R helpers   (I have already written the required R code which is giving me correct results for a given single set of data. I just wish to wish to use it for multiple data.)   I have defined a function (as given below) which helps me calculate Macaulay Duration and Modified Duration and its working fine with given set of data.   My Code -   ## ONS - PPA   duration = function(par_value,

Dear R helpers   I have a city.csv file as given below.   'city.csv' city_name1        city_name2 New York City    Buffallo         So I define   city_name = read.csv('city.csv') city1 = city_name$city_name1 city2 = city_name$city_name2   My problem is how do I repeat the names one after other say 10 times i.e. my output should be like   New York City Buffallo New York City

...ut I don't underatnd how to write  a function and thord option is to treat the input of these 20 records in a matrix form, which I had tried unsuccessfully.   Please guide me as to how do I modify the R-code to calculate Mac duration for each of tehse records and store tehm.   Regards   Madhavi Bhave   The INTERNET now has a personality. YOURS! See your Yahoo! Homepage. [[alternative HTML version deleted]]

Dear R Helpers   I have an 'instrument.csv' file with 3 instrument names and 5 rates each i.e. it has 7 columns and 6 rows (including row names).   'instrument.csv'   instrument1      instrument2           instrument3 12                         5                        14 11                         7                          7 14                       11                          3

Dear R Helpers (There is a small correction in my earlier mail. In the 'instrument.csv' file, I had mentioned only three columns. Actually there are 7 columns. I regret the error. Rest contents remains the same. Thanks) I have an 'instrument.csv' file with 7 instrument names and 5 rates each i.e. it has 7 columns and 6 rows (including row names).   'instrument.csv'  

Dear R heleprs   Suppose I have following data   Scenarios combination_names     series1    series2 Sc1 MAT2 GAU1 7.26554 8.409778 Sc2 MAT2 GAU2 7.438128 8.130275 Sc3 MAT3 GAU1 8.058422 8.06457 Sc4 MAT1 GAU2 8.179855 8.022071 Sc5 MAT3 GAU2 8.184033 8.191831 Sc6 MAT3 GAU2 7.50312 8.232425 Sc7 MAT1 GAU2 7.603291 8.200993 Sc8 MAT1 GAU1 8.221755 8.380097 Sc9 MAT3 GAU2 7.904908

Dear R helpers   I have written some function (the actual code I have pasted at the end of mail) like say   indiv_rate = function(n, rate_name, rate, rate_rf1, rate_rf2, rate_rf3, rateprob1, rateprob2, rateprob3) { ........some R commands   return(data.frame(rate_name, rates = round(rate_data, digits = 4)))   }   ## INPUT   rates = indiv_rate(n = read.csv('number.csv')$n, rate_name =

Hi ! This is Madhavi from Mumbai, India. Incidently this is my first post. I am working on Credit Scoring Model and using R, I have run the logistic regression. I have received following Output. I have two questions (a) What is the significance of "family = binomial(link = logit)". Why do I have to mention Binomial? Is it because my dependent variable assumes only two values 0 and 1?

Dear R helpers   Some particular analysis leads me to various number of output csv files depending on some conditions. Say e.g. I have output files variable1.csv, variable2.csv, .............. Problem is I don't know how many csv files been generated. They could be 4, 5 or even 10. Each file will have a column called amount.   My problem is to find filewise mean(amount) and sd(amount). I need

...          826.9019 2          826.9026          826.9019 which is I know wrong. Is there any other way I can use the function defined above to process multiple recrds. Thanking you and sincerely apologize for writing such a long mail as I wanted to be clear in my communication. Regards Madhavi Bhave ONS  = read.csv('instrument details.csv') n      = length(ONS$par_value) par_value      =  matrix(data = ONS$par_value, nrow = n, ncol = 1, byrow = TRUE) coupon_rate    =  matrix(data = ONS$coupon_rate, nrow = n, ncol = 1, byrow = TRUE) freq_coupon  =  matrix(data = ONS$frequency_copou...

Dear R-help, ? ? Chi Square Test for Goodness of Fit ? I have got a discrete data as given below (R script) ? No_of_Frauds<-c(1,1,1,1,1,1,1,1,1,2,1,1,1,1,1,1,2,1,2,2,2,1,1,2,1,1,1,1,4,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,5,1,2,1,1,1,1,1,1,1,3,2,1,1,1,2,1,1,2,1,1,1,1,1,2,1,3,1,2,1,2,14,2,1,1,38,3,3,2,44,1,4,1,4,1,2,2,1,3) ? I am trying to fit Poisson distribution to