Displaying 2 results from an estimated 2 matches for "bestpeer".
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best_err
2008 Jun 05
7
Improving data processing efficiency
...nissuers$HSICIG == arow$HSICIG, ]
industrypeers = industrypeers[
order(industrypeers$Market.Cap.13f), ]
if ( nrow(industrypeers) > 0 ) {
if ( nrow(industrypeers[industrypeers$Market.Cap.13f >=
arow$Market.Cap.13f, ]) > 0 ) {
bestpeer =
industrypeers[industrypeers$Market.Cap.13f >= arow$Market.Cap.13f, ][1,]
}
else {
bestpeer = industrypeers[nrow(industrypeers),]
}
bestpeer$Quarters.Since.IPO.Issue =
arow$Quarters.Since.IPO.Issue
#tfd...
2008 Jun 06
6
Subsetting to unique values
I want to take the first row of each unique ID value from a data frame.
For instance
> ddTable <-
data.frame(Id=c(1,1,2,2),name=c("Paul","Joe","Bob","Larry"))
I want a dataset that is
Id Name
1 Paul
2 Bob
> unique(ddTable)
Will give me all 4 rows, and
> unique(ddTable$Id)
Will give me c(1,2), but not accompanied by the name column.