search for: bernado

Displaying 1 result from an estimated 1 matches for "bernado".

Did you mean: bernardo
2010 Jun 24
5
Best way to compute a sum
> a <- 0 ; for(i in (1:200000000)) a <- a + 1/i > b <- 0 ; for(i in (200000000:1)) b <- b + 1/i > c <- sum(1/(1:200000000)) > d <- sum(1/(200000000:1)) > order(c(a,b,c,d)) [1] 1 2 4 3 > b<c [1] TRUE > c==d [1] FALSE I'd expected b being the largest, since we sum up the smallest numbers first. Instead, c is the largest, which is