Displaying 1 result from an estimated 1 matches for "beer_fit_parabola".
2010 Jul 21
3
Help me with prediction in linear model
Hi R-community,
I have the code as follows,i Fitted model as follows
lbeer<-log(beer_monthly)
t<-seq(1956,1995.2,length=length(beer_monthly)) #beer_monthly contains 400+
entries
t2=t^2
beer_fit_parabola=lm(lbeer~t+t2)
Below is not working for me.
Please help me in preparing the new data set for the below prediction
predict(beer_fit_parabola,newdata=data.frame(t=seq(1995,1998,length=20),t2=seq(1995,1998,length=20))
#it is listing all 400+ entries ,but not 20 ahead prediction.
Thanks In advanc...