Displaying 20 results from an estimated 25 matches for "bedward".
Did you mean:
edward
2010 Nov 17
2
How to catch warnings
Hello when my code executes I receive the message that were some warnings. I want to catch warning messages at run time so to print some local variables and try to understand why this warning happens.
I searched on internet and I tried withCallingHandlers(
which seems to work but as I used Rkward the result is awful. I get a prompt to copy paste a value only while at the same time my background
2010 Sep 23
3
accumulation curves
Hi,
I am trying to fit a logarithmic trendline to a scatterplot of a
species accumulation curve. I've tried abline, lines, curve and
scatter.smooth but none of these work.
Can anyone help please,
Kyran
2011 Jan 11
3
Generation of Normal Random Numbers
Dear R helpers
I have a data frame as given below
df = data.frame(A = c(776,827,836,995,855,1026,1203,1363,965,1195),
B = c(806,953,1049,1056,1243,764,1148,1162,948,1154),
C = c(959,1155,1193,1163,863,1070,1087,877,1132,944),
D = c(906,760,978,1170,1009,883,1007,960,828,113))
# Actually the real data has number of vectors and
2010 Aug 07
2
R: Confidence Intervals for logistic regression
...at you are looking for).
There also is an example on use of the 'type' argument at the end of the
page.
Stefano
-----Messaggio originale-----
Da: r-help-bounces at r-project.org
[mailto:r-help-bounces at r-project.org]Per conto di Troy S
Inviato: Friday, August 06, 2010 6:31 PM
A: Michael Bedward
Cc: r-help at r-project.org
Oggetto: Re: [R] Confidence Intervals for logistic regression
Michael,
Thanks for the reply. I believe Aline was sgiving me CI's on coefficients
as well.
So c(pred$fit + 1.96 * pred$se.fit, pred$fit - 1.96 *
pred$se.fit) gives me the CI on the logits if I unders...
2010 Aug 09
3
Regular Expression
Hi all,
>From a list of strings, I desire to filter out the followings:
1. Digits at the beginning of the strings
2. Character "SPE" following the digits (if it exists)
3. Any characters followed by hyphen
The following produces the desired result, but would like to know whether
this can be done more efficiently.
Any suggestions would be much appreciated.
dat <- c("2148
2007 Dec 17
1
RSYNC without password
Can someone help me setup "rsync" with ssh without having to type in a
password. I have tried several times to go through documentation on using
the keygen and transfer it to the other computer but I am still being asked
for the password.
--
View this message in context: http://www.nabble.com/RSYNC-without-password-tp14371565p14371565.html
Sent from the Samba - rsync mailing list
2010 Nov 12
3
Partition of a set
Hi
I am new on this forum. I am searching for a function in R which provides
all partitions of a set, say for the set
{1,2,3}
you get
{{1,2,3}}
{1,{2,3}}
{2,{1,3}}
{3,{1,2}}
{{1},{2},{3}}
. The number of partitions of a set is given by Bellsche`s number. The
number of possibilities of length (this is the number of subsets included in
the partition) of the partition is given by the partition
2010 Oct 22
2
Bayesian constrained regression method?
Hello everyone,
I am trying to estimate the parameter b.
I have Y and X1 which I know and they are both random. However, I also have
X2 which I don't know and is also random. I want to estimat b from the
model:
Y = b*X1 + ( 1 - b ) * X2
Can anyone offer some suggestions. The values of Y and X1 are both pvalues
so they are constrained in (0,1).
--
Thanks,
Jim.
[[alternative HTML version
2010 Sep 16
3
Asking Favor
Dear Prof:
My name is Chuan.I from Malaysia.I am a beginner for R.I need favor for Prof.
This is my data:
y<-c(52,55,61,66,70,61,64,73,63,59,55,90,109,85,69,72,62,59,68,113,144,104,66,73,63,58,71,122,154,106,70,69,67,61,68,104,126,88,68,70,79,65,60,70,77,68,58,75,85,71,64,59,55,61,65,83,87,79,69,68,65,76,78,94)
and I form it into matrix as below: [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
2010 Sep 15
1
retrieving object names passed indirectly to a function
Hi folks,
I'm stuck with a problem that I suspect has a trivial solution...
I have a function, call it foo, that takes a number of arguments which
it uses as parameters for a simulation. For later analysis, foo stores
the names of the objects passed to it along with the simulation
results in its output (written to a database). The objects names are
accessed with deparse(substitute(argname)).
2010 Nov 21
3
R help
Dear All,
I'm a beginner user in R and I would like to make a quadratic and
plateau model in R. Can you help please with an example?
Thanks so much
--
Ahmed M. Attia
Assistant Lecturer
El-Khattara farm Station
Agronomy Dept.,
Zgazig Univ., Egypt
Visiting Scientist
Haskell Agricultural laboratory
Agronomy and Horticultural Dept.,
Univ. of Nebraska-Lincoln
ahmedatia at zu.edu.eg
2010 Oct 11
2
compare histograms
Hello
How to compare two statistical histograms? How i can know if these histograms are equivalent or not??
Regards
[[alternative HTML version deleted]]
2010 Sep 29
1
Fitting a half-ellipse curve
Dear mailing list,
I have following array:
X2 Y2
[1,] 422.7900 6.0
[2,] 469.8007 10.5
[3,] 483.9428 11.0
[4,] 532.4917 25.5
[5,] 596.1942 33.5
[6,] 630.8496 40.5
[7,] 733.2996 45.0
[8,] 946.4779 32.0
[9,] 996.8068 35.5
[10,] 1074.3310 23.0
I do afterwards the following:
plot.new()
plot.window(xlim=c(min(X1)-50,max(X1)+50),
2010 Aug 12
5
Where the data file is stored?
Hi folks,
OS - Ubuntu 10.04
On R I create a datafile named "data". I can evoke it on R with;
> data
On R Commander
Data -> Active data set -> Select active data set -> (data) OK
only one data set there "data"
-> View data set
I can read it
-> Edit data set
showing 25 rows of data. Clicking the box shows a thick border around it. But
I couldn't
2010 Dec 14
3
peak detection
Hi,
I was wondering if anyone knows of a package that contains the ability
for peak/valley detection. Here is an example of what I'm looking for,
only problem is that it's written in Matlab.
http://www.billauer.co.il/peakdet.html
Thanks for any help in advance.
-Joe
2008 Feb 13
3
RSYNC all Directories
How would an RSYNC command look to copy all directories from one machine to
another.
I have tried the following and only get a few directories:
RSYNC --rsh=ssh -rpog / IPADDRESS:/Directory
RSYNC --rsh=ssh -rpog */ IPADDRESS:/Directory
RSYNC --rsh=ssh -rpog /* IPADDRESS:/Directory
--
View this message in context: http://www.nabble.com/RSYNC-all-Directories-tp15458934p15458934.html
Sent from the
2010 Nov 08
2
conditional probability
Dear all
I have problem with calculate probability, I have data x1,...,x10,
I want to calculate probability x11 given x1,...,x10 with two conditions.
1. x is normal
2. unknow distribution
How I can do this.
Many Thanks.
Jumlong
--
Jumlong Vongprasert Assist, Prof.
Institute of Research and Development
Ubon Ratchathani Rajabhat University
Ubon Ratchathani
2010 Oct 15
0
nomianl response model
...ments of a whole matrix (Barry Rowlingson)
7. Re: exponentiate elements of a whole matrix (Berwin A Turlach)
8. How to fix error in the package 'rgenoud' (Wonsang You)
9. Re: vertical kites in KiteChart (plotrix) (Jim Lemon)
10. Re: vertical kites in KiteChart (plotrix) (Michael Bedward)
11. Re: Lattice: arbitrary abline in multiple histograms
(Dennis Murphy)
12. Re: compare histograms (Dennis Murphy)
13. Re: Data Gaps (Dennis Murphy)
14. Date Time Objects (dpender)
15. Re: compare histograms (Michael Bedward)
16. Re: Lattice: arbitrary abline in multiple histogr...
2010 Nov 11
4
How to get a specific named element in a nested list
Hello,
I have a nested named list structure, like the following:
x <- list(
list(
list(df1,df2)
list(df3,
list(df4,df5))
list(df6,df7)))
with df1...d7 as data frames. Every data frame is named.
Is there a way to get a specific named element in x?
so, for example,
x[[c("df5")]] gives me the data frame 5?
Thank you in advance!
Best,
Friedericksen
2010 Nov 10
5
arrays of arrays
Hi All,
I want to have an array/ matrix that looks this
x<- 0 0 1 1
1 3 5
4 4
7 -1 8 9 10 6
I hope this makes sense. So basically if I want x[1,3] it will access 0 and
similarly x[4,2], -1.
Thanks in advance,
Sachin
p.s. sorry about the corporate notice.
--- Please consider the environment before printing this email ---
Allianz - Best General Insurance Company of the Year 2010*