search for: bb22

...there is a call to malloc inserted in block BB12. In order to avoid memory leak, free's are needed. The free cannot be inserted in BB23 because BB23 is not dominated by BB12. There are two ways to go I can think of here. One way is to insert a new basic block, say BB24, to connect both BB21 and BB22 and a free can be inserted into the new block BB24. The new block BB24 has to post-dominate BB12 and all the users of malloc have to happen before BB24. Another way to go is to insert a free in both BB21 and BB22. That is, a free is inserted in all the paths from BB12 to all exits after all users o...

...I have the feeling this optimization is already there somewhere) I get the following llvm code : int %test() { entry: %mat = alloca [7 x [7 x [7 x int]]], align 16 ; <[7 x [7 x [7 x int]]]*> [#uses=2] br label %cond_true cond_true: ; preds = %bb31, %bb22, %cond_true, %entry %j.1.2.ph = phi int [ 0, %entry ], [ %j.1.2.ph, %cond_true ], [ %tmp24, %bb22 ], [ 0, %bb31 ] ; <int> [#uses=4] %i.0.0.ph = phi int [ 0, %entry ], [ %i.0.0.ph, %cond_true ], [ %i.0.0.ph, %bb22 ], [ %tmp33, %bb31 ] ; <int> [#uses=...

...n block BB12. In order to >> avoid memory leak, free's are needed. The free cannot be inserted in BB23 >> because BB23 is not dominated by BB12. There are two ways to go I can think >> of here. One way is to insert a new basic block, say BB24, to connect both >> BB21 and BB22 and a free can be inserted into the new block BB24. The new >> block BB24 has to post-dominate BB12 and all the users of malloc have to >> happen before BB24. Another way to go is to insert a free in both BB21 and >> BB22. That is, a free is inserted in all the paths from BB12 to...

...alloc inserted in block BB12. In order to > avoid memory leak, free's are needed. The free cannot be inserted in BB23 > because BB23 is not dominated by BB12. There are two ways to go I can think > of here. One way is to insert a new basic block, say BB24, to connect both > BB21 and BB22 and a free can be inserted into the new block BB24. The new > block BB24 has to post-dominate BB12 and all the users of malloc have to > happen before BB24. Another way to go is to insert a free in both BB21 and > BB22. That is, a free is inserted in all the paths from BB12 to all exits &g...

...order to >>> avoid memory leak, free's are needed. The free cannot be inserted in BB23 >>> because BB23 is not dominated by BB12. There are two ways to go I can think >>> of here. One way is to insert a new basic block, say BB24, to connect both >>> BB21 and BB22 and a free can be inserted into the new block BB24. The new >>> block BB24 has to post-dominate BB12 and all the users of malloc have to >>> happen before BB24. Another way to go is to insert a free in both BB21 and >>> BB22. That is, a free is inserted in all the paths f...

...t;>> avoid memory leak, free's are needed. The free cannot be inserted in BB23 >>>> because BB23 is not dominated by BB12. There are two ways to go I can think >>>> of here. One way is to insert a new basic block, say BB24, to connect both >>>> BB21 and BB22 and a free can be inserted into the new block BB24. The new >>>> block BB24 has to post-dominate BB12 and all the users of malloc have to >>>> happen before BB24. Another way to go is to insert a free in both BB21 and >>>> BB22. That is, a free is inserted in all...

...alloc inserted in block > BB12. In order to avoid memory leak, free's are needed. The free > cannot be inserted in BB23 because BB23 is not dominated by BB12. > There are two ways to go I can think of here. One way is to insert a > new basic block, say BB24, to connect both BB21 and BB22 and a free > can be inserted into the new block BB24. The new block BB24 has to > post-dominate BB12 and all the users of malloc have to happen before > BB24. Another way to go is to insert a free in both BB21 and BB22. > That is, a free is inserted in all the paths from BB12 to all exi...

...t;>> avoid memory leak, free's are needed. The free cannot be inserted in BB23 >>>> because BB23 is not dominated by BB12. There are two ways to go I can think >>>> of here. One way is to insert a new basic block, say BB24, to connect both >>>> BB21 and BB22 and a free can be inserted into the new block BB24. The new >>>> block BB24 has to post-dominate BB12 and all the users of malloc have to >>>> happen before BB24. Another way to go is to insert a free in both BB21 and >>>> BB22. That is, a free is inserted in all...

...void memory leak, free's are needed. The free cannot be inserted in BB23 >>>>> because BB23 is not dominated by BB12. There are two ways to go I can think >>>>> of here. One way is to insert a new basic block, say BB24, to connect both >>>>> BB21 and BB22 and a free can be inserted into the new block BB24. The new >>>>> block BB24 has to post-dominate BB12 and all the users of malloc have to >>>>> happen before BB24. Another way to go is to insert a free in both BB21 and >>>>> BB22. That is, a free is ins...

Dear all, suppose I have a vector with elements as: Vec <- c(2,3,4,5,6) Now I want to have all possible combination of length 3 using those elements and without any repetition. Like, I want to have 1 possibility like 2-3-4 but not 3-2-4. Can somebody guide me how to achieve that in R? Thanks for your help.

...!: AHinMaine [full headers for details] -----BEGIN PGP SIGNATURE----- Version: PGP 6.5.8 iQCVAwUBPtOkfFPEkLgodAWVAQGivwP9EHYSqM/PfEH744F1tRL5Lxz3cRMkuWST GaT1+ZdbMx4AIfh0Zi/ZqB/WoHWK/SdmRtxAiaRwCA/llnMUE0UzWyTGTc56Dw9q vlUG0wRQ4bBVh7wUlKzs4NCe47JAkk2Dou7RgCfrIuLBm7JRScKkzyxkkOai+H/c ucTgljeOROE= =Bb22 -----END PGP SIGNATURE-----

I am using Xen 3.3 from source. My PV guest boots fine with the normal kernel and initrd options When I boot the guest with PV GRUB I only get: GNU GRUB version 0.97 (65536K lower / 0K upper memory) [ Minimal BASH-like line editing is supported. For the first word, TAB lists possible command completions. Anywhere else TAB lists the possible