search for: bayespokerguy

Hi-- I have three columns in an input file: MONTH QUARTER YEAR 2012-07 2012-3 2012 2001-07 2001-3 2001 2002-01 2002-1 2002 I want to make output like so: MONTH QUARTER YEAR 07 3 2012 07 3 2001 01 1 2002 I was having some trouble getting the regular expression to work. I think it should

Computer Friends, with the following example lines: [107] "98-610: Cell type: S; Surv(months): 6; STATUS(0=alive, 1=dead): 1" [108] "99-625: Cell type: S; Surv(months): 21; STATUS(0=alive, 1=dead): 1" i want to be able to isolate the number of months of survival for each row. is there a regular expression that can find the first instance of a ";", delete

Hello there, Much thanks in advance for any help. I have a few questions: 1) Why do I keep getting the following error: File1 <- read.csv("../RawData/File1.csv",as.is=TRUE,row.names=1) Error in file(file, "rt") : cannot open the connection In addition: Warning message: In file(file, "rt") : cannot open file '../RawData/File1.csv': No such file or

Hi all, My code looks like the following: inname = read.csv("ID_error_checker.csv", as.is=TRUE) outname = read.csv("output.csv", as.is=TRUE) #My algorithm is the following: #for line in inname #if first string up to whitespace in row in inname$name = first string up to whitespace in row + 1 in inname$name #AND ID in inname$ID for the top row NOT EQUAL ID in inname$ID for the