search for: bafoobar

hi, using the example in the grep help: txt <- c("arm","foot","lefroo", "bafoobar") i <- grep("foo",txt); i [1] 2 4 but how can i get the negation (1,3) when looking for 'foo'? thanks, m.

Would anyone care to comment if this is the best solution to this problem? > trygrep <-function(x,y) + if(grep(x,y)) + print("yes") else + print("NO") > >trygrep("foo","bafoobar") [1] "yes" > > trygrep("foo","bar") Error in if (grep(x, y)) print("yes") else print("NO") : missing value where logical needed My solution: > trygrep <-function(x,y) + if(!is.na(grep(x,y)[1])) + print("yes") else + pri...

Dear R'helpers, I guess the solution is trivial but despite some hours of testing and looking at the doc, I was unable to fix the following problem. I want to do either: for (i in 1:lat) a[i,which(a[i,]==0] <- NA or: for (i in 1:lat) a[i,which(a[i,]==-9999|a[i,]==9999|a[i,]==9998|a[i,] ==-9998)] <- NA if the word "Time" is or is not present in variable

Hello, What about an `invert` argument in grep, to return elements that are *not* matching a regular expression : R> grep("pink", colors(), invert = TRUE, value = TRUE) would essentially return the same as : R> colors() [ - grep("pink", colors()) ] I'm attaching the files that I modified (against today's tarball) for that purpose. Cheers, Romain --